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a) 541+ ( 218 - x ) = 735
218 - x = 735 - 541
218 - x = 194
x= 218 - 194
x= 24
b) 12 . x - 33 = 32 . 33
12 . x - 33 = 9 . 27
12 . x - 33 = 243
12 . x = 243 + 33
12 . x = 276
x = 276 : 12
x = 23
c) 231 - ( x-6 ) = 1339 : 13
231 - ( x- 6) = 103
x- 6 = 231- 103
x-6 = 128
x= 128 + 6
x = 134
CHÚC BN HỌC GIỎI ;)
Bài làm :
\(a,541+\left(218-x\right)=735\)
\(218-x=735-541\)
\(218-x=194\)
\(x=218-194\)
\(x=24\)
\(b,12.x-33=3^2.3^3\)
\(12x=243+33\)
\(12x=276\)
\(x=23\)
\(c,231-\left(x-6\right)=1339:13\)
\(x-6=231-103\)
\(x-6=128\)
\(x=134\)
\(d,2.x-138=2^3.3^2\)
\(2x-138=72\)
\(2x=72+138\)
\(2x=210\)
\(x=105\)
\(e,2^x.4=128\)
\(2^x=128:4\)
\(2^x=32\)
\(2^x=2^5\)
\(\Rightarrow x=5\)
\(g,x^5=x\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x=1\end{cases}}\)
Học tốt
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làm ơn giúp mình ,bạn nào làm nhanh đúng mình chọn cho nhanh nha mọi người
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1; 5.22 + (\(x\) + 3) = 52
5.4 + (\(x\) + 3) = 25
20 + (\(x\) + 3) = 25
\(x\) + 3 = 25 - 20
\(x+3\) = 5
\(x\) = 5 - 3
\(x\) = 2
Vậy \(x=2\)
2; 23 + (\(x\) - 32) = 53 - 43
8 + (\(x\) - 9) = 125 - 64
8 + (\(x\) - 9) = 61
\(x\) - 9 = 61 - 8
\(x\) - 9 = 53
\(x\) = 53 + 9
\(x\) = 62
Vậy \(x\) = 62
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a)2x-138=23.32
=>2x-138=72
=>2x =72+138
=>2x =210
=>x =210:2
=>x =105
b)20-[7(x-3)+4]=2
=>7(x-3)+4 =20-2
=>7(x-3)+4 =18
=>7(x-3) =18-4
=>7(x-3) =14
=>x-3 =14:7
=>x-3 =2
=>x =2+3
=>x =5
c)[6x-39].3.28=5628
=>[6x-39].3 =5628:28
=>[6x-39].3 =201
=>6x-39 =201:3
=>6x-39 =67
=>6x =67+39
=>6x =106
=>x =106:6
=>x =17,6
![](https://rs.olm.vn/images/avt/0.png?1311)
2x-138=2^5
2x-138=32
2x=32+138
2x=170
x=85
câu 2
27+4-(6x-12)=1
27+4-6x+12=1
31-6x+12=1
43-6x=1
6x-=43-1=42
x=42:6=7
câu 3
x:\(\frac{\left(3\cdot4\right)^3}{4^3}\)=27
x:\(\frac{3^3\cdot4^3}{4^3}\)=27
x:3^3=27
x:27=27
x=27*27=729
2x-138=2^5
2x=138+32
2x=170
x=85
3^3+2^2-6x+12=1
-6x+13+12=1
6x=24
x=4
x:(12^3/4^3)=27
x:3^3=27
x:27=27
x=729
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a)=>5.(x-3)=70-45 b)=>2x-138=8.9 c)=>10+2x=4^2 d)=>231-(x-6)=103
=>5.(x-3)=25 =>2x=138+72 =>2x=16-10 => x-6=231-103
=>x-3=25:5 =>x=210:2 =>2x=6 =>x-6=128
=>x-3=5 =>x=105 =>x=3 =>x=128+6
=>x=8 =>x=134
![](https://rs.olm.vn/images/avt/0.png?1311)
\(10+2\cdot x=4^5:4^3\)
\(\Rightarrow10+2\cdot x=4^{5-3}\)
\(\Rightarrow10+2\cdot x=4^2\)
\(\Rightarrow10+2\cdot x=16\)
\(\Rightarrow2\cdot x=16-10\)
\(\Rightarrow2\cdot x=6\)
\(\Rightarrow x=\dfrac{6}{2}=3\)
__________________
\(2\cdot x-6^2:18=3\cdot2^2\)
\(\Rightarrow2\cdot x-36:18=12\)
\(\Rightarrow2\cdot x-2=12\)
\(\Rightarrow2\cdot x=12+2\)
\(\Rightarrow2\cdot x=14\)
\(\Rightarrow x=\dfrac{14}{2}=7\)
_________________
\(70-5\cdot\left(x-3\right)=3\cdot2\)
\(\Rightarrow70-5\cdot\left(x-3\right)=6\)
\(\Rightarrow70-5x+15=6\)
\(\Rightarrow-5x+15=6-70\)
\(\Rightarrow-5x+15=64\)
\(\Rightarrow-5x=64-15\)
\(\Rightarrow-5x=49\)
\(\Rightarrow x=-\dfrac{49}{5}\)
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Ta có : (6x - 34) . 73 = 3.74
=> (6x - 34) = 3.7
=> (6x - 34) = 21
=> 6x - 81 = 21
=> 6x = 102
=> x = 17
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a) \(3^x:3^2=243\)
\(3^{x-2}=3^5\)
=> x - 2 = 5
=> x = 7
b) \(6.2^x+3.2^x=2^x.\left(6+3\right)=2^x.9=9.29=261\)
=> 2x = 9
=> x không tồn tại vì 2 khi nâng lên lũy thừa ra số chẵn.
c) d) tương tự