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a: =34x(-100)=-3400
b: =41(-76-24)=-4100
c: =-24(125-225)=2400
d: =26(-237+137)=-2600
e: =25(-63+23)=25x(-40)=-1000
![](https://rs.olm.vn/images/avt/0.png?1311)
a,=\(237.\left(-26\right)+26.137\)
=\(-6162\)\(+3572\)
=\(-2590\)
b,=\(-136+47+36.47\)
=\(47.\left(-136-36\right)\)
=\(47.-100\)
=\(-4700\)
a) 237 . (-26) + 26 . 137
= -237 . 26 + 26 . 137
= 26 . (-237 + 137)
= 26 . -100
= -2600
b) 136 . (-47) + 36 . 47
= -136 . 47 + 36 . 47
= 47 . (-136 + 36)
= 47 . -100
= -4700
c) -48 . 72 + 36 . (-304)
= -48 . 72 + 36 . 2 . (-152)
= -48 . 72 + 72 . (-152)
= 72 . (-48 + -152)
= 72 . -200
= -14400
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
(-98).(1-246)-246.98
[(1-246)-246].[(-98)+98)
1.0
0
VIẾT CÁC TÍCH SAU ĐÂY DƯỚI DẠNG MỘT LŨY THỪA
(-5)^5
237.(-26)+26.137
(237-137).(-26+26)
100.0
0
\(\left(-98\right).\left(1-246\right)-246.98\)
\(\left(-98\right).\left(-245\right)-246.98\)
\(98.245-246.98\)
\(98.\left(245-246\right)\)
\(98.\left(-1\right)\)
\(\Leftrightarrow=-98\)
\(\left(-5\right).\left(-5\right).\left(-5\right).\left(-5\right).\left(-5\right)\)
\(=\left(-5\right).5\)
\(=-25\)
\(\left(-2\right).\left(-2\right).\left(-2\right).\left(-3\right).\left(-3\right).\left(-3\right)\)
\(=\left(-2\right).3.\left(-3\right).3\)
\(=54\)
\(237.\left(-26\right)+26.137\)
\(=-6162+3562\)
\(=-2600\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
237.(-26)+26.137
=(-237).26+26.137
=26(-237+137)
=26.100
=2600
63.(-25)+25.(-23)
=-63.25+25.(-23)
=25.(-63+(-23))
=25.86
=2150
-2.(-3).(-2014)<0
(-1).(-2)....(-2014)>0
ko hiểu chỗ nào nhắn cho mình
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{36}{1\cdot3\cdot5}+\frac{36}{3\cdot5\cdot7}+\frac{36}{5\cdot7\cdot9}+...+\frac{36}{25\cdot27\cdot29}\)
\(=9\left[\frac{4}{1\cdot3\cdot5}+\frac{4}{3\cdot5\cdot7}+\frac{4}{5\cdot7\cdot9}+...+\frac{4}{25\cdot27\cdot29}\right]\)
\(=9\left[\frac{1}{1\cdot3}-\frac{1}{3\cdot5}+\frac{1}{3\cdot5}-\frac{1}{5\cdot7}+...+\frac{1}{25\cdot27}-\frac{1}{27\cdot29}\right]\)
\(=9\left[\frac{1}{3}-\frac{1}{783}\right]=9\cdot\frac{260}{783}=\frac{260}{87}\)
Đặt \(A=\frac{36}{1.3.5}+\frac{36}{3.5.7}+\frac{36}{5.7.9}+...+\frac{36}{25.27.29}\)
\(\Rightarrow\frac{1}{9}A=\frac{4}{1.3.5}+\frac{4}{3.5.7}+\frac{4}{5.7.9}+...+\frac{4}{25.27.29}\)
\(\Rightarrow\frac{1}{9}A=\frac{1}{1.3}-\frac{1}{3.5}+\frac{1}{3.5}-\frac{1}{5.7}+...+\frac{1}{25.27}-\frac{1}{27.29}\)
\(\Rightarrow\frac{1}{9}A=\frac{1}{1.3}-\frac{1}{27.29}\)
\(\Rightarrow\frac{1}{9}A=\frac{261}{783}-\frac{1}{783}\)
\(\Rightarrow\frac{1}{9}A=\frac{260}{783}\)
\(\Rightarrow A=\frac{260}{783}\div\frac{1}{9}\)
\(\Rightarrow A=\frac{2340}{783}=\frac{260}{87}\)
237.(-36)+36.137
= -36 . (237 - 137)
= -36 . 100
= -3600
237.(-36)+36.137
=237.(-36)-(-36).137
=(-37).(237-137)
=(-37).100
=-3700