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![](https://rs.olm.vn/images/avt/0.png?1311)
Ư(18) = 1, 2, 3, 6, 9, 18
Ư(45) = 1, 3, 5, 9, 15, 45
Ư(28) = 1, 2, 4, 7, 14, 28
Ư(40) = 1, 2, 4, 5, 8, 10, 20, 40
![](https://rs.olm.vn/images/avt/0.png?1311)
Ư(64) = {1,2,4,8,64}
Ư(72) = {1,2,3,4,6,9,72}
Ư(17) ={1,17}
![](https://rs.olm.vn/images/avt/0.png?1311)
Ư( 48)=1,2,3,4,6,7,12,14,24,28
Ư(30)=1,2,3,5,6,10,15,30
![](https://rs.olm.vn/images/avt/0.png?1311)
Ư ( 16 ) = { 1 ; -1 ; 2 ; -2 ; 4 ; -4 ; 8 ; -8 ; 16 ; -16 }
Ư ( 64 ) = { 1 ; -1 ; 2 ; -2 ; 4 ; -4 ; 8 ; -8 ; 16 ; -16 ; 32 ; -32 ; 64 ; -64 }
Ư ( 35 ) = { 1 ; -1 ; 5 ; -5 ; 7 ; -7 ; 35 ; -35 }
Ư ( 20 ) = { 1 ; -1 ; 2 ; -2 ; 4 ; -4 ; 5 ; -5 ; 10 ; -10 ; 20 ; -20 }
Ư ( 37 ) = { 1 ; -1 ; 37 ; -37 }
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ư( 9 ) = { 1 ; 3 ; 9 }
Ư( 8 ) = { 1 ; 2 ; 4 ; 8 }
Ư( 9 ) = { 1 ; 3 ; 9 }
Ư ( 8 ) = { 1 ; 2 ; 4 ; 8 }
\(Ư\left(9\right)\in\left\{1;3;9\right\}\\ Ư\left(8\right)\in\left\{1;2;4;8\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ư{17}={1,17}
B[4]={8,12,16,20,24,28,32.36.40,44,48,52,56,60,64,68,72,76,80,84,88,92,96}
B[2]={2,6,18} với điều kiện X thuộc Ư[54]
Ư[28]={7} với điều kiện là X thuộc Ư[35]
![](https://rs.olm.vn/images/avt/0.png?1311)
i: \(18=3^2\cdot2\)
=>\(Ư\left(18\right)=\left\{1;-1;2;-2;3;-3;6;-6;9;-9;18;-18\right\}\)
k: \(24=2^3\cdot3\)
=>\(Ư\left(-24\right)=Ư\left(24\right)=\left\{1;-1;2;-2;3;-3;4;-4;6;-6;8;-8;12;-12;24;-24\right\}\)
l: \(12=2^2\cdot3\)
=>\(Ư\left(12\right)=Ư\left(-12\right)=\left\{1;-1;2;-2;3;-3;4;-4;6;-6;12;-12\right\}\)
m: \(27=3^3\)
=>\(Ư\left(27\right)=\left\{1;-1;3;-3;9;-9;27;-27\right\}\)
Ư(30)=\(\hept{\begin{cases}\\\end{cases}1;2;3;5;6;10;15;30}\)
ư(42)=\(\hept{\begin{cases}\\\end{cases}1;2;3;6;7;14;21}\);42
ư(17)=(1;17)
ư(28)=(1;2;4;7;12;28)