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b, \(3737.43-4343.37=\left(37.101\right).43-\left(43.101\right).37=0\)
suy ra B = 0
c, \(D=\frac{2^{12}\left(13+65\right)}{2^{10}.104}+\frac{3^{10}\left(11+5\right)}{3^9.2^4}=\frac{2^{12}.78}{2^{10}.104}+\frac{3^{10}.16}{3^9.2^4}\)
\(=\frac{2^{12}.2.39}{2^{10}.2^3.13}+\frac{3^{10}.2^4}{3^9.2^4}=\frac{39}{13}+3=6\)
\(A=\frac{72^2.54^2}{1084}=\frac{\left(72.54\right)^2}{1084}=\frac{3888^2}{1084}=\frac{3888.3888}{1084}=\frac{972.3888}{271}=\frac{3779136}{271}\)
ta có
3737 . 43 - 4343 . 37 = ( 3700 + 37) . 43 - (4300+43) . 37
= 3700 . 43 + 37 .43 - 4300 . 37 + 43 . 37
= 43 . 37 . ( 3700 . 43 - 4300 . 37)
= 1591 . (159100 - 159100)
= 1591 . 0
= 0
vậy \(\frac{3737.43-4343.37}{2+4+6+....+100}\)= 0
đap số 0
a, A = \(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
\(A=\frac{2^{10}\left(13+65\right)}{2^8.2^2.26}=\frac{2^{10}.78}{2^{10}.26}=\frac{78}{26}=3\)
Vậy A = 3
b, \(B=\frac{72^3.54^2}{108^4}=\frac{72^3.54^2}{\left(54.2\right)^4}=\frac{72^3.54^2}{54^4.2^4}=\frac{72^3}{54^2.2^4}=\frac{\left(8.9\right)^3}{\left(6.9\right)^2.2^4}\)
\(=\frac{\left(2^3\right)^3.9^3}{6^2.9^2.2^4}=\frac{2^9.9^3}{2^2.3^2.9^2.2^4}=\frac{2^9.9^3}{2^6.9^3}=\frac{2^9}{2^6}=2^3=8\)
Vậy B = 8
c, \(C=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\frac{11.3^{29}.3^{30}}{2^2.3^{28}}=\frac{11.3^{29}.3.3^{29}}{2^2.3^{28}}=\frac{\left(11-3\right)3^{29}}{2^2.3^{28}}\)
\(=\frac{2^3.3^{29}}{2^2.3^{28}}=2.3=6\)
Vậy C = 6
d, \(D=\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}=\frac{\left(3.2^{18}\right)^2}{11.2^{35}-\left(2^4\right)^9}=\frac{3^2.2^{36}}{11.2^{35}-2^{36}}=\frac{3^2.2^{36}}{\left(11-2\right)2^{35}}=\frac{3^2.2}{9}=2\)
Vậy D = 2
\(D=\frac{3737.43-4343.37}{2+4+6+...+100}\)
\(\Rightarrow D=\frac{37.101.43-4343.37}{2+4+6+...+100}\)
\(\Rightarrow D=\frac{37.4343-4343.37}{2+4+6+...+100}\)
\(\Rightarrow D=\frac{4343.\left(37-37\right)}{2+4+6+...+100}\)
\(\Rightarrow D=\frac{4343.0}{2+4+6+...+100}\)
\(\Rightarrow D=\frac{0}{2+4+6+...+100}\)
\(\Rightarrow D=0\)
Vậy D = 0
ngắn gọn