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1/x+x+1+x+2+x+3+...+x+2006+2007=2007
------------------------------------------=2007-2007
------------------------------------------=0
x+x+x+...+x+1+2+3+...+2006=0
2007.x+(1+2+...+2006)=0
2007.x+(2006+1).[(2006-1)+1]:2=0
2007.x+2013021=0
2007.x=0-2013021
x=-2013021:2007
x=-1003
2/x+x+1+x+2+...+x+198=401-201-200-199
199.x+(1+2+...+198)=-199
199.x+(1+198).[(198-1)+1]:2=-199
199.x+19701=-199
199.x=-199-19701
x=-19900:199
x=-100
3/x+x+1+x+2+...+x+2008=2010-2010-2009
2009.x+(2008+1).[(2008-1)+1]:2=-2009
2009.x+2017036=-2009
2009.x=-2009-2017036
x=-2019045:2009
x=-1005
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(23x5x7)(52x73)/(2x5x72)2=23x(5x52)x(7x73)/22x52x72x2=23x53x74/22x52x74=2x5=10
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a) 315+( 146-x)=401
146 - x = 401 - 315
146 - x = 86
x = 146 - 86
x = 60
b) (6x -39) :3 = 201
(6.x -39) = 201x3
(6.x -39) = 603
6.x = 603+39
6.x = 642
x = 624:6
x = 107
c) 23+ 3x = 56:53
23+ 3x =53
23+ 3x = 125
3x = 125 - 23
3x = 102
x = 102:3
x = 34
d) 9x-1 = 9
9x-1 = 91
Suy ra: x-1 =1
x = 1+1
x = 2
e) x4 = 16
x4 = 24
Suy ra: x = 2
f) 2x : 25 = 1
2x = 1x 25
2x = 25
Suy ra : x =5
g) 2x + 1 . 22014 = 22015
2x + 1 = 22015 : 22014
2x + 1 = 2
2x = 2 - 1
x = 1:2
x = \(\frac{1}{2}\)
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Ta có: 1+2-3+...+200-201
Để riêng số 1 ta được:
2-3+3-4+....+200-201 có: 100 cặp
= (-1)+(-1)+...+(-1)
= (-1) x 100 = -100
=> 1+2-3+3-4+...+200-201
= 1 + (-100) = -99
Vậy 1+2-3+...+200-201 = -99