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Mk nghĩ số 1000 ở mẫu bn nên sửa thành 2000 ms đúng
2014 × 2015 - 15/2000 + 2015 × 2013
= (2013 + 1) × 2015 - 15/2000 + 2015 × 2013
= 2013 × 2015 + (2015 - 15)/2000 + 2015 × 2013
= 2013 × 2015 + 2000/2000 + 2015 × 2013
= 1
![](https://rs.olm.vn/images/avt/0.png?1311)
=[2013*2014*+2014*2015+2015*2016]*[\(1\frac{1}{3}-1\frac{1}{3}\)]
=A*0
=0
nhớ k nha mấy friends/
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\(\frac{45.47-33}{45.46+12}\)
= \(\frac{45.\left(46+1\right)-33}{45.46+12}\)
= \(\frac{45.46+45-33}{45.46+12}\)
= \(\frac{45-33}{12}\)
= \(1\)
=> biểu thức trên = 1
\(\frac{2013.2014+2000}{2014.2014-15}\)
\(=\frac{2013.2014+2000}{2014.\left(2013+1\right)-15}\)
\(=\frac{2013.2014+2000}{2014.2013+2014-15}\)
\(=\frac{2000}{2014-15}\)
\(=\frac{2000}{1999}\)
=> biểu thức trên < 1
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{2012+2013x2014}{2014x2015-2016}\)\(=\frac{2012+2013x2014}{2014x\left(2013+2\right)-2016}\)
\(=\frac{2012+2013x2014}{2014x2013+4028-2016}\)
\(=\frac{2012+2013x2014}{2014x2013+2012}\)
\(=1\)
\(\frac{2012+2013x2014}{2014x2015-2016}\)
= \(\frac{2012+2013x2014}{2014x\left(2013+2\right)-2016}\)
= \(\frac{2012+2013x2014}{2014x2013+4028-2016}\)
= \(\frac{2012+2013x2014}{2014x2013+2012}\)
= 1
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![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{2012+2013x2014}{2014x2015-2016}\)
= \(\frac{2012+4054182}{4058210-2016}\)
= \(\frac{4056194}{4056194}\)
= \(\frac{1}{1}\)
= \(1\)
Answer : \(1\)
\(\frac{2012+2013.2014}{2014.2015-2016}\)
\(=\frac{2012+2013.2014}{2014.\left(2013+2\right)-2016}\)
\(=\frac{2012+2013.2014}{2014.2013+2014.2-2016}\)
\(=\frac{2012}{4028-2016}\)
\(=\frac{2012}{2012}\)
\(=1\)
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36.47-18.94=18.2.47-18.94=18.94-18.94=0
=>2013.2014(36.47-18.94)=0
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![](https://rs.olm.vn/images/avt/0.png?1311)
2/
a) \(\frac{4}{1\cdot5}+\frac{4}{5\cdot9}+\frac{4}{9\cdot13}+\frac{4}{13\cdot17}+\frac{4}{17\cdot21}\)
\(=\left(1-\frac{1}{5}+\frac{1}{5}-\frac{1}{9}+....+\frac{1}{17}-\frac{1}{21}\right)\)
\(=1-\frac{1}{21}=\frac{20}{21}\)
b) \(\left(1-\frac{1}{2}\right)\cdot\left(1-\frac{1}{3}\right)\cdot\left(1-\frac{1}{4}\right)\cdot...\cdot\left(1-\frac{1}{2017}\right)\)
\(=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot..\cdot\frac{2016}{2017}\)
\(=\frac{1}{2017}\)
c) \(A=2000-5-5-5-..-5\)(có 200 số 5)
\(A=2000-\left(5\cdot200\right)\)
\(A=2000-1000\)
\(A=1000\)
=13+2013x2014/2014x2013+2013-2000
=13+2014x2013/2014x2013+13
=1