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a)
\(\frac{2}{3}\div x-\frac{1}{2}=\frac{1}{3}\)
\(\Rightarrow\frac{2}{3}\div x=\frac{1}{3}+\frac{1}{2}\)
\(\Rightarrow\frac{2}{3}\div x=\frac{5}{6}\)
\(\Rightarrow x=\frac{2}{3}\div\frac{5}{6}\)
\(\Rightarrow x=\frac{4}{5}\)
Vậy \(x=\frac{4}{5}\)
b)
\(\frac{3}{4}.x+\frac{2}{5}=\frac{5}{2}\)
\(\Rightarrow\frac{3}{4}.x=\frac{5}{2}-\frac{2}{5}\)
\(\Rightarrow\frac{3}{4}.x=\frac{21}{10}\)
\(\Rightarrow x=\frac{21}{10}\div\frac{3}{4}\)
\(\Rightarrow x=\frac{14}{5}\)
Vậy \(x=\frac{14}{5}\)
Các bước chi tiết mình không trình bày ra nha.
a) 2/3:x-1/2=1/3
2/3:x=1/3+1/2
2/3:x=5/6
x=2/3:5/6
x=4/5
b) 3/4.x+2/5=5/2
3/4.x=5/2-2/5
3/4.x=21/10
x=21/10:3/4
x=14/5
![](https://rs.olm.vn/images/avt/0.png?1311)
\((6-4\frac{1}{2}):0,03+(3\frac{1}{20}-2,65):4+\frac{2}{5}\)
\((6-4,5):0,03+(3,05-2,65):4+0,4\)
\(=1,5:0,03+0,4:4+0,4\)
\(=50+(0,4\cdot2):4\)
\(=50+0,2\)
\(=50,2\)
Chúc bạn học tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{1}{3}\) + \(\frac{5}{6}\): \(\left(x-2\frac{1}{5}\right)\)= \(\frac{3}{4}\)
<=> \(\frac{5}{6}\):\(\left(x-2\frac{1}{5}\right)\)= \(\frac{3}{4}\)- \(\frac{1}{3}\)
<=> \(\frac{5}{6}\) : \(\left(x-2\frac{1}{5}\right)\) = \(\frac{5}{12}\)
<=> \(\left(x-2\frac{1}{5}\right)\) = \(\frac{5}{6}\) : \(\frac{5}{12}\)
,<=> \(\left(x-2\frac{1}{5}\right)\)= 2
<=. x = 2 + \(\frac{11}{5}\)
<=> x = \(\frac{21}{5}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
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1/1x2 + 1/2x3+ 1/3x4+....+1/2009x2010
= 1/1-1/2 + 1/2-1/3+ 1/3-1/4+...+1/2009-1/2010
= 1/1-1/2010
= 2009/2010
\(\frac{1}{1\cdot2}+\cdot\cdot\cdot+\frac{1}{2009\cdot2010}\)
\(=1-\frac{1}{2}+\cdot\cdot\cdot+\frac{1}{2009}-\frac{1}{2010}\)
\(=1-\frac{1}{2010}\)
\(=\frac{2009}{2010}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2\frac{3}{5}-2=\frac{13}{5}-2\)
\(=\frac{3}{5}\)
nha
bằng 3 phần 5