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a) \(\left(x-4\right)\left(x+3\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-4=0\\x+3=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=4\\x=-3\end{cases}}\)
Vậy \(x\in\left\{-3;4\right\}\)
b)\(\left(x^2+16\right)\left(x^2-16\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x^2+16=0\\x^2-16=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\sqrt{-16}\\x=\sqrt{16}=4\end{cases}}\)
Vậy \(x=4\)
\(\left(x-4\right)\left(x+3\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-4=0\\x+3=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=4\\x=-3\end{cases}}\)
\(\left(x^2+16\right)\left(x^2-16\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x^2+16=0\\x^2-16=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x^2=-16\left(loại\right)\\x^2=16\end{cases}}\Rightarrow x=\left(\pm4\right)^2\)
\(\left(x-2\right)\left(x+4\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-2=0\\x+4=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=2\\x=-4\end{cases}}\)
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\(\frac{3}{2}\left|x\right|+\frac{1}{2}\left|x\right|=2+2\)
\(2\left|x\right|=4\)
\(\left|x\right|=2\)
\(x=-2\)hoặc x = 2
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De ma de minh giai cho , ko can chi can nick 1 cai la douc roi :
(x+5)+(x-9)=x+2
x+5+x+9=x+2
2x+14=x+2
ko viet vao vo nhe : trong truong hop nay ta bo bot 2 ben moi ben 1 con x
x+14=2
x=2-14
Vay x=-12, x=am 12 nhe . Dau tru to viet hoi nho chut
Cac ban xem va an **** cho minh nhe . Cam on
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a)\(\frac{1}{4}x+2x=\frac{9}{2}\)
\(x.\left(\frac{1}{4}+2\right)=\frac{9}{2}\)
\(x.\frac{9}{4}=\frac{9}{2}\)
x\(=\frac{9}{2}:\frac{9}{4}\)
\(x=2\)
b)x=2 và x =(-1)
c)x=4
a. 25%x +2x=4,5
0,25x +2x =4,5
(0,25+2)x=4,5
2,25 x=4,5
x=4,5:2,25
x=2
\(3\left(x-2\right)^2-25=2=>3\left(x-2\right)^2=27=>\left(x-2\right)^2=\frac{27}{3}=9\)
\(=>\left(x-2\right)^2=3^2=\left(-3\right)^2=>\hept{\begin{cases}x-2=3\\x-2=-3\end{cases}=>\hept{\begin{cases}x=5\\x=-1\end{cases}}}\)
3(x-2)^2-25=2
=> 3(x-2)^2=27
=> (x-2)^2=9
=> x-2=3 hoặc x-2=-3
=>x=5 hoặc x=-1