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![](https://rs.olm.vn/images/avt/0.png?1311)
\(=\frac{2^3.1.3.5+2^3.3.5.7+2^3.5.7.9+...+2^3.97.99.101}{1.3.5+3.5.7+5.7.9+...+97.99.101}\)
\(=\frac{2^3\left(1.3.5+3.5.7+5.7.9+...+97.99.101\right)}{1.3.5+3.5.7+5.7.9+...+97.99.101}=2^3=8\)
![](https://rs.olm.vn/images/avt/0.png?1311)
ta có tử =2.(1.3.5)+2.(3.5.7)+2.(5.7.9)+....+2.(97.99.101)
=2.(1.3.5+3.5.7+5.7.9+....+97.99.101)
mà mẫu =1.3.5+3.5.7+5.7.9+...+97.99.101
suy ra A=2
![](https://rs.olm.vn/images/avt/0.png?1311)
A =2.6.10+6.10.14+10.14.18+...+194.198.202/1.3.5+3.5.7+5.7.9+7.9.11+...+97.99.101
=2.2.2(1.3.5)+2.2.2(3.5.7)+2.2.2(5.7.9)+...+2.2.2(97.99.101)/1.3.5+3.5.7+5.7.9+...+97.99.101
=2.2.2/1
=2^3/1
=8/1
=8
Đúng like nha pạn !
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\frac{2\cdot6\cdot10+6\cdot10\cdot14+...+194\cdot198\cdot202}{1\cdot3\cdot5+3\cdot5\cdot7+...+97\cdot99\cdot101}=\frac{\left(1\cdot3\cdot5+3\cdot5\cdot7+...+97\cdot99\cdot101\right)\cdot2}{1\cdot3\cdot5+3\cdot5\cdot7+...+97\cdot99\cdot101}=2\)
chết, cái này mình sai, của thanh mới đúng , phải lấy 2*2*2=8
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\dfrac{2.6.10+6.10.14+10.14.18+..+194.198.202}{1.3.5+3.5.7+5.7.9+..+97.99.101}\)
\(=\dfrac{2^3.1.3.5+2^3.3.5.7+2^3.5.7.9+...+2^3.97.99.101}{1.3.5+3.5.7+7.9.11+...+97.99.101}\)
\(=\dfrac{2^3.\left(1.3.5+3.5.7+7.9.11+...+97.99.101\right)}{1.3.5+3.5.7+5.7.9+...+97.99.101}=2^3=8\)
![](https://rs.olm.vn/images/avt/0.png?1311)
A =\(\dfrac{2.6.10+6.10.14+10.14.18+...+194.198.202}{1.3.5+3.5.7+5.7.9+...+97.99.101}\)
\(\Rightarrow\)A=\(\dfrac{1.3.5\left(1.3.5+3.5.7+5.7.9+...+97.99.101\right)}{1.3.5+3.5.7+5.7.9+...+97.99.101}\)
A=\(\dfrac{15}{1}\)=15