![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
( 20152015/20162016 + 20172017/20162016 ) . x - 1 = 2016
2.x-1=2016
2x=2017
x=2017:2
x=1008,5
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\Rightarrow2^y\left(2^{x-y}+1\right)=72\)
Vì \(2^{x-y}+1\) lẻ nên \(2^y\left(2^{x-y}+1\right)=72=2^3\cdot9\)
\(\Rightarrow\left\{{}\begin{matrix}y=3\\2^{x-3}+1=9\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}y=3\\2^{x-3}=8=2^3\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=6\\y=3\end{matrix}\right.\)
Vậy \(\left(x;y\right)=\left(6;3\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có \(2^x-2^y=1024\Rightarrow x>y\)
Do đó \(2^y\left(2^{x-y}-1\right)=2^{10}\)
Lại có \(2^{x-y}-1\) lẻ và là ước 10 nên \(2^{x-y}-1=1\Rightarrow2^y=2^{10}\)
\(\Rightarrow y=10\Rightarrow2^{x-10}=2^1\Rightarrow x=11\)
Vậy \(\left(x;y\right)=\left(11;10\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(xy+2x+y=5\)
\(xy+2x+y+2=7\)
\(x\left(y+2\right)+\left(y+2\right)=7\)
\(\left(x+1\right)\left(y+2\right)=7\)
=> \(\left(x+1\right);\left(y+2\right)\inƯ\left(7\right)=\left\{-1;1;-7;7\right\}\)
Ta có bảng sau:
x+1 | 1 | -1 |
x | 0 | -2 |
y+2 | 7 | -7 |
y | 5 | -9 |
Vậy ta có các cặp x; y : (0;5),(-2;-9)