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/2,8-x/+1,2=/-4,6/
/2,8-x/ =4,6- 1,2
/2,8-x/ =3,4
=> 2,8-x=3,4 hoặc 2,8-x=-3,4
=> x=-0,6 hoặc x=6,2
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: |x+1,2|>=0
=>|x+1,2|-3,5>=-3,5 hay A>=-3,5
Nên GTNN của A =-3,5 khi:
x+1,2=0
x=0-1,2
x=-1,2
Vậy HTNN của A =-3,5 khi x=-1,2
mk k chắc nữa
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Ta có: \(9\cdot5^x=6\cdot5^6+3\cdot5^6\)
\(\Leftrightarrow9\cdot5^x=9\cdot5^6\)
\(\Leftrightarrow5^x=5^6\)
hay x=6
b) Ta có: \(2^{2x+1}+4^{x+3}=264\)
\(\Leftrightarrow4^x\cdot2+4^x\cdot64=264\)
\(\Leftrightarrow4^x=4\)
hay x=1
![](https://rs.olm.vn/images/avt/0.png?1311)
bài 2)
a)|12,1x+12,1.0,1|=12,1
<=> |12,1(x+0,1)|=12,1
<=>\(\left[\begin{array}{nghiempt}12,1\left(x+0,1\right)=12,1\\12,1\left(x+0,1\right)=-12,1\end{array}\right.\)
<=> \(\left[\begin{array}{nghiempt}x=0,9\\x=-1,1\end{array}\right.\)
b) |0,2x-3,1|+|0,2+3,1|=0
<=>|0,2x-3,1|+3,3=0
ta có |A|>=0
=> pt trên vô nghiệm
bài 1) a) 6,5+1,2+3,5-5,2+6,5-4,8
=(6,5+3,5+6,5)-(5,2-1,2+4,8)
=15,5-8,8=24,6
tt nha bạn
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\left|x\right|=3,5\)
\(\Rightarrow\left[{}\begin{matrix}x=3,5\\x=-3,5\end{matrix}\right.\)
b) \(\left|1-x\right|+0,73=3\)
\(\Rightarrow\left|1-x\right|=3-0,73\)
\(\Rightarrow\left|1-x\right|=2,27\)
\(\Rightarrow\left[{}\begin{matrix}1-x=2,27\\1-x=-2,27\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=-1,27\\x=3,27\end{matrix}\right.\)
c) \(\dfrac{-5}{8}+x=\dfrac{4}{9}\)
\(\Rightarrow x=\dfrac{4}{9}-\left(\dfrac{-5}{8}\right)\)
\(\Rightarrow x=\dfrac{77}{72}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài làm
\(\sqrt{121}-1,2x=3,5x+9\)
\(11-1,2x=3,5x+9\)
\(11-1,2x-3,5x-9=0\)
\(2-4,7x=0\)
\(4,7x=2\)
\(x=2,35\)
Vậy x = 2,35
# Học tốt #
\(\sqrt{121}-1,2x=3,5x+9\)
\(11-1,2x=3,5x+9\)
\(11-1,2x-3,5x+9=0\)
\(11-\left(1,2x+3,5x\right)+9=0\)
\(11-4,7x+9=0\)
\(11-4,7x=0-9\)
\(11-4,7x=-9\)
\(4,7x=11-\left(-9\right)\)
\(4,7x=11+9\)
\(4,7x=20\)
\(x=20\div4,7\)
\(\Rightarrow x=\frac{20}{4,7}\)
(SAI THÌ THÔI)
#Học tốt!!!
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,121-\left(115+x\right)=3x-\left(25-9-5x\right)-8\\ 121-115-x=3x-25+9+5x-8\\ 6-x=8x-24\\ 8x+x=-24-6\\ 9x=-30\\ x=-\dfrac{30}{9}=-\dfrac{10}{3}\\ ----\\ b,2^{x+2}.3^{x+1}.5^x=10800\\ \left(2.3.5\right)^x.2^2.3=10800\\ 30^x.12=10800\\ 30^x=\dfrac{10800}{12}=900=30^2\\ Vậy:x=2\)
\(\sqrt{121}-1,2x=3,5x+9\)
\(\Leftrightarrow\sqrt{11^2}-9=3,5x+1,2x\)
\(\Leftrightarrow11-9=4,7x\)
\(\Leftrightarrow4,7x=2\)
\(\Leftrightarrow x=\frac{20}{47}\)