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a: \(0.2\left(7\right)+0.3\left(5\right)\)
\(=\dfrac{5}{18}+\dfrac{16}{45}\)
\(=\dfrac{225}{810}+\dfrac{288}{810}\)
\(=\dfrac{19}{30}\)
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\(=1:\dfrac{154}{15}:\dfrac{5}{12}\cdot\dfrac{77}{180}\)
\(=1\cdot\dfrac{15}{154}\cdot\dfrac{12}{5}\cdot\dfrac{77}{180}\)
\(=\dfrac{15\cdot12\cdot77}{154\cdot5\cdot180}=\dfrac{1}{10}\)
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\(a,\dfrac{15^3}{5^4}\)
\(=\dfrac{\left(3\cdot5\right)^3}{5^4}\)
\(=\dfrac{3^3\cdot5^3}{5^4}\)
\(=\dfrac{3^3}{5}\)
\(=\dfrac{27}{5}\)
\(---\)
\(b,\dfrac{21^3}{7^4}\)
\(=\dfrac{\left(3\cdot7\right)^3}{7^4}\)
\(=\dfrac{3^3\cdot7^3}{7^4}\)
\(=\dfrac{3^3}{7}\)
\(=\dfrac{27}{7}\)
\(---\)
\(c,\dfrac{6^6}{3^8}\)
\(=\dfrac{\left(2\cdot3\right)^6}{3^8}\)
\(=\dfrac{2^6\cdot3^6}{3^8}\)
\(=\dfrac{2^6}{3^2}\)
\(=\dfrac{64}{9}\)
#\(Toru\)
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\(\begin{array}{l}a)0,36.\frac{{ - 5}}{9}\\ = \frac{{36}}{{100}}.\frac{{ - 5}}{9}\\ = \frac{9}{{25}}.\frac{{ - 5}}{9}\\ = \frac{{ - 1}}{5}\\b)\frac{{ - 7}}{6}:1\frac{5}{7}\\ = \frac{{ - 7}}{6}:\frac{{12}}{7}\\ = \frac{{ - 7}}{6}.\frac{7}{{12}}\\ = \frac{{ - 49}}{{72}}\end{array}\)
Chú ý: Khi tính toán, nếu phân số chưa ở dạng tối giản thì ta nên rút gọn về dạng tối giản để tính toán thuận tiện hơn.
a)0,2(7)+0,3(5)
=518+1645=1930
b)1:10,2.0,42(6):0,41(6).0,42(7)
110,2.0,42(6):0,41(6).0,42(7)
=551.3275:512.77180=551.3275:512.77180
=246457375=246457375