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13 tháng 2 2019

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13 tháng 2 2019

pascal bạn oi

2 tháng 2 2019

ko hỉu

Ko hiểu nốt

uses crt;

var a:array[1..100]of integer;   

i,n,t,t1,t2,t3,min,max:integer;   

kt:boolean;

begin

clrscr;

write('Nhap n='); readln(n);

for i:=1 to n do 

begin     

write('A[',i,']='); readln(a[i]); 

end;

writeln('Day so ban vua nhap la: ');

for i:=1 to n do 

write(a[i]:4);

writeln;

t:=0;

for i:=1 to n do 

t:=t+a[i];

kt:=true;

for i:=2 to trunc(sqrt(t)) do 

if t mod i=0 then     

begin       

kt:=false;       

break;     

end;

writeln('Tong cua day so la: ',t);

if (kt=true) and (t>1) then writeln(t,' la so nguyen to')

else writeln(t,' khong la so nguyen to');

writeln('Cac so o vi tri le cua day so la: ');

t1:=0;

for i:=1 to n do 

if i mod 2=1 then     

begin       

write(a[i]:4);       

t1:=t1+a[i];     

end;

writeln;

writeln('Tong cac so o vi tri le cua day so la: ',t1);

if trunc(sqrt(t1))=sqrt(t1) then writeln(t1,' la so chinh phuong')

else writeln(t1,' khong la so chinh phuong');

writeln('Cac so o vi tri chan cua day so la: ');

t2:=0;

for i:=1 to n do 

if i mod 2=0 then     

begin       

write(a[i]:4);       

t2:=t2+a[i];     

end;

writeln;

writeln('Tong cac so o vi tri chan cua day so la: ',t2);

t3:=0;

for i:=1 to t2 do 

if t2 mod i=0 then t3:=t3+i;

if t3=t2 then writeln(t2,' la so hoan hao')

else writeln(t2,' khong la so hoan hao');

max:=a[1];

min:=a[1];

for i:=1 to n do 

begin     

if max<a[i] then max:=a[i];     

if min>a[i] then min:=a[i]; 

end;

writeln('So lon nhat cua day la: ',max);

writeln('So nho nhat cua day la: ',min);

writeln('Tong cua so lon nhat va so nho nhat la: ',max+min);

readln;

end.

uses crt;

var a:array[1..100]of integer;

n,i,t,kt,j,t1,t2,t3,max,min:integer;

begin

clrscr;

write('Nhap n='); readln(n);

for i:=1 to n do 

begin

write('A[',i,']='); readln(a[i]);

end;

writeln('Day so ban vua nhap la: ');

for i:=1 to n do 

  write(a[i]:4);

writeln;

t:=0;

for i:=1 to n do 

  t:=t+a[i];

writeln('Tong cua day so vua nhap la: ',t);

kt:=0;

for i:=2 to trunc(sqrt(t)) do 

  if t mod i=0 then

begin

kt:=1;

break;

end;

if (kt=0) and (t>1) then writeln(t,' la so nguyen to');

else writeln(t,' khong la so nguyen to');

t1:=0;

writeln('Cac so o vi tri le cua day la: ');

for i:=1 to n do 

  if i mod 2=1 then 

begin

write(a[i]:4);

t1:=t1+a[i];

end;

writeln;

writeln('Tong cac so o vi tri le la: ',t1);

if trunc(sqrt(t1))=sqrt(t1) then writeln(t1,' la so chinh phuong')

else writeln(t1,' khong la so chinh phuong');

t2:=0;

writeln('Cac so o vi tri chan la: ');

for i:=1 to n do 

  if i mod 2=0 then 

begin

write(a[i]:4);

t2:=t2+a[i];

end;

writeln;

writeln('Tong cac so o vi tri chan la: ',t2);

t3:=0;

for i:=1 to t2 do 

if t2 mod i=0 then t3:=t3+i;

if t3=t2 then writeln(t2,' la so hoan hao')

else writeln(t2,' khong la so hoan hao');

max:=a[1];

min:=a[1];

for i:=1 to n do 

begin

if max<a[i] then max:=a[i];

if min>a[i] then min:=a[i];

end;

writeln('Gia tri lon nhat la: ',max);

writeln('Gia tri nho nhat la: ',min);

writeln('Tong cua hai so lon nhat va nho nhat la: ',max+min);

readln;

end.

30 tháng 1 2021

cái dong đầu bị lỗi chỗ a[i] á xem lại hộ mình với

27 tháng 11 2023

Mấy đề bài em gửi lên đều thiếu em kiểm tra lại ghi tất cả đầy đủ ý của câu đó vào 1 câu hỏi nhé.

uses crt;

var n,i,d,dem,kt,t,kt1,t1,t2,t3,max,min,x,j:integer;   

a,b:array[1..100]of integer;   

st:string;

begin

clrscr;

write('Nhap n='); readln(n);

str(n,st);

d:=length(st);

for i:=1 to d do 

val(st[i],a[i],x);

dem:=1;

b[1]:=a[1];

for i:=1 to d do 

begin     

kt:=0;     

for j:=1 to dem do       

if a[i]=b[j] then kt:=1;     

if kt=0 then       

begin           

inc(dem);           

b[dem]:=a[i];       

end; 

end;

writeln('Cac chu so cua ',n,' la: ');

for i:=1 to dem do 

write(b[i]:4);

writeln;

t:=0;

for i:=1 to d do 

t:=t+a[i];

writeln('Tong cac chu so cua ',n,' la: ',t);

kt1:=0;

for i:=2 to trunc(sqrt(t)) do 

if t mod i=0 then     

begin       

kt1:=1;       

break;     

end;

if (kt1=0) and (t>1) then writeln(t,' la so nguyen to')

else writeln(t,' khong la so nguyen to');

writeln('Cac chu so o vi tri le cua ',n,' la: ');

t1:=0;

for i:=1 to d do 

if i mod 2=1 then     

begin       

write(a[i]:4);       

t1:=t1+a[i];     

end;

writeln;

writeln('Tong cac chu so o vi tri le la: ',t1);

if trunc(sqrt(t1))=sqrt(t1) then writeln(t1,' la so chinh phuong')

else writeln(t1,' khong la so chinh phuong');

writeln('Cac chu so o vi tri chan cua ',n,' la: ');

t2:=0;

for i:=1 to d do 

if i mod 2=0 then     

begin       

write(a[i]:4);       

t2:=t2+a[i];     

end;

writeln('Tong cac chu so o vi tri chan la: ',t2);

t3:=0;

for i:=1 to t2 do 

if t2 mod i=0 then t3:=t3+i;

if (t3=t2) and (t2>0) then writeln(t2,' la so hoan hao')

else writeln(t2,' khong la so hoan hao');

max:=a[1];

min:=a[1];

for i:=1 to d do 

begin     

if max<a[i] then max:=a[i];     

if min>a[i] then min:=a[i]; 

end;

writeln('Chu so lon nhat cua ',n,' la: ',max);

writeln('Chu so nho nhat cua ',n,' la: ',min);

writeln('Tong cua chung la: ',max+min);

readln;

end.

Mình sẽ tạm hiểu đề này là viết chương trình in ra các số nguyên tố lớn hơn hoặc bằng n nha

#include <bits/stdc++.h>

using namespace std;

int n,m,i;

//chuongtrinhcon

bool ktnt(int n)

if (n<2) return false; 

for (int i=2; i*i<=n; i++) 

if (n%i==0) return false; 

return true;

}

int main()

{

cin>>n;

cout<<"Cac so nguyen to nho hon bang n thoa man yeu cau la"<<endl;

for (int i=2; i<=n; i++) 

if (ktnt(i)) cout<<i<<" ";

}

uses crt;

var n,i:integer;

st:string;

begin

clrscr;

readln(n);

if n mod 4=0 then writeln('n chia het cho 4')

else writeln('n khong chia het cho 4');

str(n,st);

writeln(length(st));

for i:=length(st) downto 1 do write(st[i]);

readln;

end.

uses crt;

var i,j,kt:integer;

begin

clrscr;

for i:=100 to 1 do write(i:4);

writeln;

for i:=2 to 100 do 

  begin

kt:=0;

for j:=2 to trunc(sqrt(i)) do

  if i mod j=0 then kt:=1;

if kt=0 then write(i:4);

end;

readln;

end.