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Giải :
a) x + ( x + 1 ) + ( x + 2 ) + ... + ( x + 50 ) = 2040
=> 51x + ( 1 + 2 + 3 + ... + 50 ) = 2040
=> 51x + ( 50 + 1 ) . 50 : 2 = 2040
=> 51x + 1275 = 2040
=> 51x = 765
=> x = 15
b) 1 + 2 + 3 + ... + x = 300
=> ( x + 1 ) . x : 2 = 300
=> ( x + 1 ) . x = 600
=> ( x + 1 ) . x = 25 . 24
=> x = 24
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
b, 2 + 4 + 6 +.....+2x =210
=>2*(1+2+3+....+x) =210
=> 1+2+3+....+x = 105
=> (x+1)*x : 2 = 105
=> (x+1)*x = 210
=> (x+1)*x = 15*14
=>x=14
c) [(x - 300)^2 - 280 ] * 2 = 19440
=> (x - 300)^2 - 280 = 9720
=> (x - 300)^2 = 10000 =1002
=> x - 300 =100
=> x=400
a, 3x-1+ 5* 3x-1 = 162
3x-1 * (5 + 1) = 162
3x-1 * 6 = 162
3x-1 = 27 = 33
=> x-1=3
=> x=4
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
1/ \(\frac{1}{2}x+1=\frac{2}{3}\)
\(\frac{1}{2}x=\frac{2}{3}-1\)
\(\frac{1}{2}x=-\frac{1}{3}\)
\(x=\left(-\frac{1}{3}\right)\div\frac{1}{2}\)
\(x=-\frac{2}{3}\)
2/ \(100+x=200+300\)
\(100+x=500\)
\(x=500-100\)
\(x=400\)
Chúc bạn học tốt nha!
Chúc bạn học tốt nha!
Chúc bạn học tốt nha!
Chúc bạn học tốt nha!
\(\frac{1}{2}x+1=\frac{2}{3}\Rightarrow\frac{1}{2}x=\frac{2}{3}-1=-\frac{1}{3}\Rightarrow x=-\frac{1}{3}:\frac{1}{2}=-\frac{2}{3}\)-2/3 vây..
\(100+x=200+300\\ x=500-100=100\) vậy...
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bài 2
x+(x+1)+(x+2)+....+(x+30)=1240
\(\Rightarrow\)(x+x+x+...+x)+(1+2+3+....+30)=1240
có 31 SH có 30 SH
\(\Rightarrow\)31x+(30+1)x30:2=1240
\(\Rightarrow\)31x+465=1240
\(\Rightarrow31x=1240-465\)
\(\Rightarrow31x=775\)
\(\Rightarrow x=775:31\)
\(\Rightarrow x=25\)
Vậy x=25
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a.\left[x\cdot\left(x+1\right)\right]:2=136\\ x\cdot\left(x+1\right)=136\cdot2\\ x\cdot\left(x+1\right)=2\cdot2\cdot2\cdot17\cdot2\\ x\cdot\left(x+1\right)=\left(2\cdot2\cdot2\cdot2\right)\cdot17\\ x\cdot\left(x+1\right)=16\cdot17\\ =>x=16\\ b.\left[x\cdot\left(x+1\right)\right]:2=300\\ x\cdot\left(x+1\right)=3\cdot2\cdot2\cdot5\cdot5\cdot2\\ x\cdot\left(x+1\right)=\left(3\cdot2\cdot2\cdot2\right)\cdot\left(5\cdot5\right)\\ x\cdot\left(x+1\right)=24\cdot25\\ =>x=24\\ c.\left[x\cdot\left(x+1\right)\right]:2=561\\ x\cdot\left(x+1\right)=2\cdot3\cdot11\cdot17\\ x\cdot\left(x+1\right)=\left(17\cdot2\right)\cdot\left(3\cdot11\right)\\ x\cdot\left(x+1\right)=34\cdot33\\ =>x=33\)
1+2+3+...........+ x=300
\(\frac{x.\left(x+1\right)}{2}=300\)
x.(x+1)=300.2
x.(x+1)=600
x.(x+1)=24.25
=>x=24
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