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a,
A=1−3−5−7−9−...−97−99a)A=1−3−5−7−9−...−97−99
=1−(3+5+7+...+99)=1−(3+5+7+...+99)
=1−(99+3).[(99−3):2+1]2=1−(99+3).[(99−3):2+1]2
=1−2499=−2498=1−2499=−2498
b)B=1+3−5−7+9+...+97−99b)B=1+3−5−7+9+...+97−99
=(−8)+(−8)+(−8)+...+(−8)+97−99=(−8)+(−8)+(−8)+...+(−8)+97−99
=(−8).12+(−2)=−98=(−8).12+(−2)=−98
c)C=1−3−5+7+9−11−13+15+...+97−99c)C=1−3−5+7+9−11−13+15+...+97−99
=0+0+0+0+0+...+0−99=0+0+0+0+0+...+0−99
=−99
![](https://rs.olm.vn/images/avt/0.png?1311)
58+(-7)+9+(-11)+13+(-15)=[58+(-11)]+{[(-7)+(-15)]+[13+9]}
=47+[(-22)+22]
=47+0=47
Vậy nha :)
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a, \(\dfrac{5}{9}.\dfrac{10}{11}+\dfrac{5}{9}.\dfrac{14}{11}-\dfrac{5}{9}.\dfrac{15}{11}=\dfrac{5}{9}.\left(\dfrac{10}{11}+\dfrac{14}{11}-\dfrac{15}{11}\right)=\dfrac{5}{9}.\dfrac{9}{11}=\dfrac{5}{11}\)
b, \(\dfrac{6}{7}.\dfrac{8}{13}+\dfrac{6}{13}.\dfrac{9}{7}-\dfrac{3}{13}.\dfrac{6}{7}\)\(=\dfrac{6}{7}.\left(\dfrac{8}{13}-\dfrac{3}{13}\right)+\dfrac{6}{13}.\dfrac{9}{7}=\dfrac{6}{7}.\dfrac{5}{13}+\dfrac{54}{91}=\dfrac{30}{91}+\dfrac{54}{91}=\dfrac{84}{91}=\dfrac{12}{13}\)
Bạn ơi, gõ latex cho dễ nhìn nhé!
![](https://rs.olm.vn/images/avt/0.png?1311)
\(1+2-3-4+5+...+994-995-996+997+998\)
\(=1+\left(2-3-4+5\right)+...+\left(994-995-996+997\right)+998\)
\(=1+0+...+0+998=999\)
Chúc bạn học tốt!!!
1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + 9 + .........+ 994 - 995 - 996 + 997 + 998
= 1 + ( 2 - 3 - 4 + 5 ) + ... + ( 994 - 995 - 996 + 997 ) + 998
= 1 + 0 + ... + 0 + 998 = 999
#ĐinhBa
![](https://rs.olm.vn/images/avt/0.png?1311)
= -6 ez quá
Cả cách gải nha