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Ta có :
7ab = 2 . ab7 + 21
<=> 700 + ab = 20 . ab + 14 + 21
<=> 700 + ab = 20 . ab + 35
=> 700 - 35 = 20 . ab - ab
=> 665 = 19 . ab
=> ab = 35
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Giải
Ta có : 83=512 ; 93=729 ; 103=1000
=>\(\hept{\begin{cases}\left(18-3.x\right)^3=9^3=729\\\overline{729}=\overline{7ab}\end{cases}}\)\(\Leftrightarrow\hept{\begin{cases}18-3.x=9\\a=2;b=9\end{cases}}\)\(\Leftrightarrow\hept{\begin{cases}x=3\\a=2;b=9\end{cases}}\)
Vậy ...
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2.(x+4)=87-25
=>2.(x+4)=62
=>x+4=62:2
=>x+4=31
=>x=31-4=>x=27
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a) -65 .( 87 - 17 ) -87 .( 17 - 65 )
= ( - 65 ) . 87 + 17 - 87 . 17 + 65
= { ( - 65 ) + 65 } . 87 + 17
= 0 . 87 + 17
= 17
b) -215 . [ 14 + ( -236 ) ] + 215 . ( 14 - 236 )
= -215 . 14 + ( - 236 ) + 215 . 14 - 236
= [ ( - 215 ) + 215 ] . 14 + { ( - 236 - 236 }
= 0 . 14 + 0
= 0
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a. 4.37.25.50.12
=(4.25).(50.12).37
=100.600.37
=2220000
\(a.\left(4.50\right).\left(25.12\right).37\)
\(=200.300.37=2220000\)
\(b.\left(46+54\right)+\left(17+83\right)\)
\(=100+100=200\)
\(c.87.\left(36+69\right)=87.105=9135\)
\(d.\left(135+65\right)+\left(360+40\right)\)
\(=200+400=600\)
\(e.\left(463+137\right)+\left(318+22\right)\)
\(=600+340=940\)
=>700+ab=4.(10.ab+7)+87
=>700+ab=40ab+28+87
=>700-28-87=40ab-ab
=>585=39.ab
=>ab=15