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a: =25(15+45*3)
=25*150
=3750
b: \(=-10\left(25+75-50\right)=-10\cdot50=-500\)
c: =>3^x-2=27
=>x-2=3
=>x=5
d: =>2x-5=-4
=>2x=1
=>x=1/2
e: =>2(x-1)^2=32
=>(x-1)^2=16
=>x-1=4 hoặc x-1=-4
=>x=-3 hoặc x=5
f: =>25(x+3)=75
=>x+3=3
=>x=0
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\left(x-2018\right)\cdot3=0\)
\(\Leftrightarrow x-2018=0\)
\(\Leftrightarrow x=2018\)
b) \(25\left(x-8\right)=0\)
\(\Leftrightarrow x-8=0\)
\(\Leftrightarrow x=8\)
c) \(25+\left(15+x\right)=75\)
\(\Leftrightarrow15+x=50\)
\(\Leftrightarrow x=35\)
![](https://rs.olm.vn/images/avt/0.png?1311)
có tổng bằng 0 thì suy ra cả 2 số bằng nhau
còn có tích bằng 0 thì suy ra 1 trong 2 số bằng 0
Bạn cứ thế làm nhé
![](https://rs.olm.vn/images/avt/0.png?1311)
a) -9-25=(7-x)-(25+7)
<=> −9−25=7−x−25−7
<=> -9=7-x-7
<=> -9=-x
<=> x=9
b) (x-5)(x+8)=0
<=> x-5=0 hoặc x+8=0
<=> x=5 hoặc x=-8
d) Đề sai, x đâu???
...
\(c,0< \left|x-7\right|< 3\)
\(0< x-7< 3\)
\(7< x< 10\)
\(\Rightarrow x\in\left\{8;9\right\}\)
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(-1).(-1)\(^2\).(-1)\(^3\).....(-1)\(^{100}\)
\(\Rightarrow\)(-1).1.(-1).1.....(-1).1
có tất cả 50 số -1
có tất cả 50 số 1
\(\Rightarrow\) \([\)(-1).50\(]\).\([\)1.50\(]\)
=-50.50=0
![](https://rs.olm.vn/images/avt/0.png?1311)
1. Thực hiện phép tính bằng cách hợp lí :
a) (-46) + (-125) + 46 + 25 = [(-46)+46] + [(-125)+25]
= 0+(-100) = -100
b) 25.(-15) + 25.(-5) + (-20).75 = 25.[(-15)+(-5)] + (-20).75
= 25.(-20) + (-20).75 = (-20).(25+75) = (-20).100 = -2000
c) (-151)+(-37)+(-42)+(-63)+142 =(-151)+[(-37)+(-63)]+[(-42)+142]
= (-151) + [(-100) + 100] = -151
d)32+(-149)+(-311)+(-89)+(-51) = 32+[(-149)+(-51)] + [(-311)+(-89)]
= 32+[(-200)+(-400)] = 32+(-600) = -568
e)-65.(87-17)-87.(17-65) = (-65).87 - (-65).17 - 87.17 + 87.65
= (-65).87 + 65.17 - 87.17 + 87.65 = [(-65).87+87.65] + 65.(17-87)
= 65.(-70) = -4550
g) -43.(53-16) - 53.(16-43) = (-43).53 - (-43).16 - 53.16 + 53.43
= (-43).53 + 43.16 - 53.16 + 53.43 = [(-43).53+53.43] + 16.(43-53)
= 16.(-10) = -160
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1/2×(2×x-3)+105/2=-137/2
1/2×(2×x-3)=-137/2-105/2
1/2×(2×x-3)=-242/2
2×x-3=-242/2:1/2
2×x-3=-242
2.x=(-242)+3
2.x=239
x=239:2
x=239/2
A,-12×25-25×75-25×13
=[(-12)-75-13].25
=(-100).25
-2500
B,-50/7×49/10-35/2×-10/7+ -25/3× -9/5
=(-35)-(-25)+(-13)
=-23
C,-354+265-156+125
=[(-354)-156]+(265+125)
=(-510)+277
=-233
D,-74+40-50+16-35
=(-74)+40+(-50)+16+(-35)
=[(-74)+(-35)]+[40+(-50)+16]
=(-109)+26
=-83
E,-2/3×4/5+-4/5×4/3-0,125
=-2/3.4/5+4/5.(-4/3)-0,125
=4/5.[-2/3+(-4/3)]-0,125
=4/5.(-2)-0,125
=-8/5-0,125
=(-1,6)+(-0,125)
=-1,725
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a) \(x.9,1+x.1,9=26,4\)
\(\Rightarrow x.\left(9,1+1,9\right)=26,4\)
\(\Rightarrow x.11=26,4\)
\(\Rightarrow x=\dfrac{26,4}{11}=\dfrac{12}{5}\)
Vậy \(x=\dfrac{12}{5}\)
b) \(x.9,9+x:10=12,5\)
\(\Rightarrow x.9,9+x.\dfrac{1}{10}=12,5\)
\(\Rightarrow x.\left(9,9+\dfrac{1}{10}\right)=12,5\)
\(\Rightarrow x.10=12,5\)
\(\Rightarrow x=\dfrac{12,5}{10}=\dfrac{5}{4}\)
Vậy \(x=\dfrac{5}{4}\)
c) \(x:0,1-x:4-x.0,75=2,25\)
\(\Rightarrow x.\dfrac{1}{0,1}-x.\dfrac{1}{4}-x.0,75=2,25\)
\(\Rightarrow x.10-x.\dfrac{1}{4}-x.0,75=2,25\)
\(\Rightarrow x.\left(10-\dfrac{1}{4}-0,75\right)=2,25\)
\(\Rightarrow x.9=2,25\)
\(\Rightarrow x=\dfrac{2,25}{9}=\dfrac{1}{4}\)
Vậy \(x=\dfrac{1}{4}\)
d) \(x:0,25-x=51,6\)
\(\Rightarrow x.\dfrac{1}{0,25}-x=51,6\)
\(\Rightarrow x.4-x=51,6\)
\(\Rightarrow x.\left(4-1\right)=51,6\)
\(\Rightarrow x.3=51,6\)
\(\Rightarrow x=\dfrac{51,6}{3}=\dfrac{86}{5}\)
Vậy \(x=\dfrac{86}{5}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
3 . [ 25 - ( x - 10 ) ] - 75 = 0
3 . [ 25 - ( x - 10 ) ] = 75
25 - ( x - 10 ) = 75 : 3
25 - ( x - 10 ) = 25
x - 10 = 25 - 25
x - 10 = 0
x = 0 + 10
x = 10
Vậy x = 10
\(3\cdot\left[25-\left(x-10\right)\right]-75=0\)
\(3\cdot\left[25-\left(x-10\right)\right]=0+75\)
\(3\cdot\left[25-\left(x-10\right)\right]=75\)
\(25-\left(x-10\right)=75:3\)
\(25-\left(x-10\right)=25\)
\(x-10=25-25\)
\(x-10=0\)
\(x=0+10\)
\(x=10\)