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42.43/210
= (22)2.(22)3/210
= 24.26/210
= 210/210
= 1
Ủng hộ mk nha ☆_☆^_-
\(\frac{4^2.4^3}{2^{10}}=\frac{4^{2+3}}{2^{2.5}}=\frac{4^5}{4^5}=1\)
\(M=\dfrac{2^2.3^2.4^2.....20^2}{1.3.2.4.3.5.4.6.5.7.6.8.7.9....19.21}=\)
\(=\dfrac{2^2.3^2.4^2....20^2}{1.2.3^2.4^2....19^2.20.21}=\dfrac{2.20}{21}=\dfrac{40}{21}\)
\(N=\dfrac{1}{2}.\dfrac{2}{3}.\dfrac{3}{4}.....\dfrac{10}{11}=\dfrac{1}{11}\)
4^2.4^3/2^10=(2^2)^2/(2^2)^10=2^4/2^20=1/2^16
Nho cho minh nhe
Yen tam minh hoc roi khong sai dau
\(\frac{4^2.4^3}{2^{10}}=\frac{2^4.2^6}{2^{10}}=\frac{2^{10}}{2^{10}}=1\)
\(\frac{4^2.4^3}{2^{10}}=\frac{4^5}{2^{10}}=\frac{\left(2^2\right)^5}{2^{10}}=\frac{2^{10}}{2^{10}}=1\)
hai vế mỗi vế có kết qua bằng 1
khi cộng 2 vầ ta có kết quả chính bằng 2
vậy thôi
dễ
\(\frac{4^2.4^3}{2^{10}}+\frac{3^2.3^3}{3^5}\)
\(=\frac{\left(2^2\right)^2.\left(2^2\right)^3}{2^{10}}+\frac{3^{2+3}}{3^5}\)
\(=\frac{2^4.2^6}{2^{10}}+\frac{3^5}{3^5}\)
\(=\frac{2^{4+6}}{2^{10}}+1\)
\(=\frac{2^{10}}{2^{10}}+1\)
\(=1+1\)
\(=2\)
\(1,\\ a,=\left(\dfrac{1}{4}\right)^3\cdot32=\dfrac{1}{64}\cdot32=\dfrac{1}{2}\\ b,=\left(\dfrac{1}{8}\right)^3\cdot512=\dfrac{1}{512}\cdot512=1\\ c,=\dfrac{2^6\cdot2^{10}}{2^{20}}=\dfrac{1}{2^4}=\dfrac{1}{16}\\ d,=\dfrac{3^{44}\cdot3^{17}}{3^{30}\cdot3^{30}}=3\\ 2,\\ a,A=\left|x-\dfrac{3}{4}\right|\ge0\\ A_{min}=0\Leftrightarrow x=\dfrac{3}{4}\\ b,B=1,5+\left|2-x\right|\ge1,5\\ A_{min}=1,5\Leftrightarrow x=2\\ c,A=\left|2x-\dfrac{1}{3}\right|+107\ge107\\ A_{min}=107\Leftrightarrow2x=\dfrac{1}{3}\Leftrightarrow x=\dfrac{1}{6}\)
\(d,M=5\left|1-4x\right|-1\ge-1\\ M_{min}=-1\Leftrightarrow4x=1\Leftrightarrow x=\dfrac{1}{4}\\ 3,\\ a,C=-\left|x-2\right|\le0\\ C_{max}=0\Leftrightarrow x=2\\ b,D=1-\left|2x-3\right|\le1\\ D_{max}=1\Leftrightarrow x=\dfrac{3}{2}\\ c,D=-\left|x+\dfrac{5}{2}\right|\le0\\ D_{max}=0\Leftrightarrow x=-\dfrac{5}{2}\)
\(\frac{4^2.4^3}{2^{10}}=\frac{\left(2^2\right)^2.\left(2^2\right)^3}{2^{10}}\)
\(=\frac{2^4.2^6}{2^{10}}\)
\(=\frac{2^{10}}{2^{10}}=1\)
\(x=\frac{4^2.4^3}{2^{10}}=\frac{4^5}{2^{10}}=\frac{\left(2^2\right)^5}{2^{10}}=\frac{2^{10}}{2^{10}}=1\)
TL
c2 = \(\frac{4^2.4^3}{2^{10}}\)=\(\frac{2^4.2^6}{2^{10}}\)= 1
HT