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người ta ko bt thì hỏi , đừng có mak ns mấy câu vô văn hóa thế nhá
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a) 0,16 + 1,3
= \(\frac{4}{25}+\frac{13}{10}\)
= \(\frac{40}{250}+\frac{325}{250}\)
= \(\frac{73}{50}\)
b) 1,3 + 0,12 . \(2\frac{8}{11}\)
= \(\frac{13}{10}+\frac{3}{25}\times\frac{30}{11}\)
= \(\frac{13}{10}+\frac{18}{55}\)
= \(\frac{143}{110}+\frac{36}{110}\)
= \(\frac{179}{110}\)
c) 0,6 + 1,6
= \(\frac{3}{5}+\frac{8}{5}\)
= \(\frac{11}{5}\)
d) 3,6 + 1,36 \(\times\)\(2\frac{1}{5}\)
= \(\frac{18}{5}+\frac{34}{25}\times\frac{11}{5}\)
= \(\frac{18}{5}+\frac{374}{125}\)
= \(\frac{450}{125}+\frac{374}{125}\)
= \(\frac{824}{125}\)
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Lời giải:
a. $x(\frac{4}{5}x-1)(0,1x-10)=0$
$\Rightarrow x=0$ hoặc $\frac{4}{5}x-1=0$ hoặc $0,1x-10=0$
Nếu $\frac{4}{5}x-1=0$
$\Rightarrow x=1: \frac{4}{5}=\frac{5}{4}$
Nếu $0,1x-10=0$
$\Rightarrow x=10:0,1=100$
Vậy $x=0; \frac{5}{4}; 100$
b.
$(\frac{1}{4}x-1)-(\frac{5}{6}x+2)-(1-\frac{5}{8}x)=0$
$(\frac{1}{4}x-\frac{5}{6}x+\frac{5}{8}x)-(1+2+1)=0$
$\frac{1}{24}x-4=0$
$x=4: \frac{1}{24}=96$
Tìm x biết
\(\frac{0,1\left(6\right)+0,\left(3\right)}{0,\left(3\right)+1,1\left(6\right)}\)- x=0,(2)
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\(\frac{0,1\left(6\right)+0,\left(3\right)}{0,\left(3\right)+1,1\left(6\right)}-x=0,\left(2\right)\)
\(\Rightarrow\frac{\frac{1}{6}+\frac{1}{3}}{\frac{1}{3}+\frac{7}{6}}-x=\frac{2}{9}\)
\(\Rightarrow\frac{\frac{1}{2}}{\frac{3}{2}}-x=\frac{2}{9}\)
\(\Rightarrow\frac{1}{3}-x=\frac{2}{9}\)
\(\Rightarrow x=\frac{1}{3}-\frac{2}{9}=\frac{1}{9}\)
Vậy \(x=\frac{1}{9}\)
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a, 30,24 + 30,24 + 30,24 + 30,24 x 7 - 30,24 : 0,1
= 30,24 x 3 + 30,24 x 7 - 30,24 : 0,1
= 30,24 x 10 - 30,24 : 0,1
= 30,24 x 10 - 30,24 x 10
= 0
b, 2 giờ 30 phút x 8 + 2,5 giờ x 3 - 150 phút
= 2,5 giờ x 8 + 2,5 giờ x 3 - 150 phút
= 2,5 giờ x 8 + 2,5 giờ x 3 - 2,5 giờ
= 2,5 giờ x 10
= 25 giờ
c, 1/2 : 0,5 - 1/4 : 0,25 + 1/8 : 0,125 - 1/10 : 0,1
= 1/2 x 2 + 1/4 x 4 + 1/8 x 8 - 1/10 x 10
= 1 + 1 + 1 - 1
= 2
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* 0,00(24)
= \(\dfrac{24-0}{9900}=\dfrac{24}{9900}\)
0,(12) = \(\dfrac{12}{99}\)
1,3(4)
= \(1+\dfrac{34-3}{90}=1+\dfrac{31}{90}=\dfrac{121}{90}\)
0,1(25)
\(=\dfrac{125-1}{900}=\dfrac{124}{900}=\dfrac{31}{225}\)
0,(123)= \(\dfrac{123}{999}\)
* tìm x:
a) 0,875 . x = \(\dfrac{3}{4}+2\dfrac{5}{8}\)
\(\dfrac{7}{8}\) . x = \(\dfrac{3}{4}+\dfrac{21}{8}\)
\(\dfrac{7}{8}\) . x = \(\dfrac{6}{8}+\dfrac{21}{8}\)
\(\dfrac{7}{8}\) . x = \(\dfrac{27}{8}\)
x = \(\dfrac{27}{8}\) : \(\dfrac{7}{8}\)
x = \(\dfrac{27}{8}\) . \(\dfrac{8}{7}\)
x = \(\dfrac{27}{7}\)
b) 0,(12) : 1,(6) = x : 0,3
\(\dfrac{12}{99}\) : \(\dfrac{105}{99}\) = x : \(\dfrac{3}{10}\)
\(\dfrac{12}{99}\) . \(\dfrac{99}{105}\) = x : \(\dfrac{3}{10}\)
\(\dfrac{12}{105}\) = x : \(\dfrac{3}{10}\)
\(\dfrac{12}{105}\) . \(\dfrac{3}{10}\) = x
\(\dfrac{6}{175}\) = x
\(\Rightarrow x+\dfrac{1}{10}=-\dfrac{8}{3}\Rightarrow x=-\dfrac{83}{30}\)
(x+0,1).3+8=0
⇔(x+0,1).3=-8
⇔x+0,1=\(-\dfrac{8}{3}\)
⇔x=\(-\dfrac{83}{30}\)