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a) Ta có (14 – 4) x 3 = 14 x 3 – 4 x 3
b) 29 x 2 – 9 x 2 = (29 – 9) x 2
= 20 x 2
= 40
7 x 214 – 7 x 14 = 7 x (214 – 14)
= 7 x 200
= 1 400
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\(\frac{9}{14}-\frac{x}{7}:\frac{5}{3}=\frac{3}{14}\Leftrightarrow\frac{9}{14}-\frac{3x}{35}=\frac{3}{14}\Leftrightarrow\frac{3x}{35}=\frac{3}{7}\Leftrightarrow3x=15\Leftrightarrow x=5\)
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\(\frac{1}{2}\cdot\frac{18}{14}+\frac{1}{2}\cdot\frac{3}{14}-\frac{1}{2}\cdot\frac{7}{14}\)
\(=\frac{1}{2}\left(\frac{18}{14}+\frac{3}{14}-\frac{7}{14}\right)\)
\(=\frac{1}{2}\cdot1=\frac{1}{2}\)
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9/14 - x/7 : 5/3 = 3/14
9/14 - x x 1/7 x 3/5 = 3/14
x x 3/35 = 9/14 - 3/14
x x 3/35 = 3/7
x = 3/7 : 3/35
x = 5
vậy x =5
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Đề Bài :\(\frac{9}{14}\)- \(\frac{x}{7}\): \(\frac{5}{3}\)= \(\frac{3}{14}\)
ta có : \(\frac{9}{14}\)- \(\frac{x}{7}\)= \(\frac{3}{14}\)x \(\frac{5}{3}\)= \(\frac{5}{14}\)
\(\frac{x}{7}\)= \(\frac{9}{14}\)- \(\frac{5}{14}\)= \(\frac{4}{14}\)
\(\frac{4}{14}\)= \(\frac{x}{7}\)=> \(\frac{4}{14}\)= \(\frac{2}{7}\)=> x = 2
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9/5 : 7/4 + 3/4 x 8/7
= (9/5 : 8/7) x (7/4 + 3/4)
= 63/40 x 5/2
= 63/16
7 x 3/14 - 1/14
= 3/2 - 1/4
= 5/4
\(\dfrac{9}{5}:\dfrac{7}{4}+\dfrac{3}{4}\times\dfrac{8}{7}\)
\(=\dfrac{9}{5}\times\dfrac{4}{7}+\dfrac{3}{4}\times\dfrac{8}{7}\)
\(=\dfrac{36}{35}+\dfrac{6}{7}\)
\(=\dfrac{66}{35}\)
\(7\times\dfrac{3}{14}-\dfrac{1}{14}\)
\(=\dfrac{3}{2}-\dfrac{1}{14}\)
\(=\dfrac{10}{7}\)