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\(\Rightarrow a^2-1⋮8\\ \Rightarrow a^2⋮9\\ \Rightarrow a=\pm3\)
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4 \(\times\) (\(x-1\))3 - 1 = 3
4 \(\times\) (\(x\) - 1)3 = 3 + 1
4 \(\times\) (\(x-1\))3 = 4
(\(x-1\))3 = 4:4
(\(x-1\))3 = 1
\(x-1=1\)
\(x\) = 1 + 1
\(x\) = 2
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`(x - 2)/3 = (x + 1)/4`
`(x - 2) . 4 = (x + 1) . 3`
`<=> 4x - 8 = 3x + 3`
`<=> 4x - 3x = 3 + 8`
`<=> (4 - 3)x = 11`
`=> x = 11`
`=>` `x = 11`
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Sửa đề : \(\frac{3}{4}x-\frac{1}{4}=2\left(x-3\right)-\frac{1}{4}x\)
\(\frac{3}{4}x-\frac{1}{4}=2x-6-\frac{1}{4}x\)
\(\frac{3}{4}x-\frac{1}{4}=\frac{7}{4}x+2x\)
\(-x-\frac{1}{4}=2x\)
\(-x-\frac{1}{4}-2x=0\)
\(-3x-\frac{1}{4}=0\)
\(-3x=\frac{1}{4}\Leftrightarrow x=-\frac{1}{12}\)
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\(\Leftrightarrow\frac{3}{4}x-\frac{1}{4}=2x-6+\frac{1}{4}x\)
\(\Leftrightarrow\frac{3}{4}x-2x-\frac{1}{4}x=-6+\frac{1}{4}\)
\(\Leftrightarrow\frac{-3}{2}x=\frac{-23}{4}\)
\(\Leftrightarrow x=\frac{23}{6}\)
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Ta có:
3/4x-1/4=2(x-3)+1/4x
<=>3/4x-1/4x=2x-6+1/4
<=>x-2x=-23/4
<=>-x=-23/4
<=>x=23/4.
Vậy x=23/4
x - 1 = 4x - 8
<=> 3x = 7
<=> x = 7/3
Vậy...
\(x-1=4x-8\)
\(\Rightarrow-1+8=4x-x\)
\(\Rightarrow7=3x\)
\(\Rightarrow x=\frac{7}{3}\)