Question

[Nguyễn Thùy Linh]

Tính:

B=\(\left(\frac{3}{25}-1,12\right):\frac{3}{7}:[\left(3\frac{1}{2}-3\frac{2}{3}\right)]\)

Answer 1

[★๖ۣۜNɠυүễη ๖ۣۜTɦáĭ ๖ۣۜTɦịηɦ★]

\(B=\left(\frac{3}{25}-1,12\right):\frac{3}{7}:\left[\left(3\frac{1}{2}-3\frac{2}{3}\right)\right]\)

\(B=\left(\frac{3}{25}-\frac{28}{25}\right):\frac{3}{7}:\left[\left(\frac{7}{2}-\frac{11}{3}\right)\right]\)

\(B=\frac{-25}{25}:\frac{3}{7}:\left[\left(\frac{21}{6}-\frac{22}{6}\right)\right]\)

\(B=-1:\frac{3}{7}:\frac{-1}{6}\)

\(B=\frac{-1}{1}.\frac{7}{3}:\frac{-1}{6}\)

\(B=\frac{-7}{3}:\frac{-1}{6}\)

\(B=\frac{-7}{3}.\frac{6}{-1}=\frac{-42}{-3}=14\)

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