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\(\frac{3^{-m}}{81}=27\)
\(=>3^{-m}=27\cdot81\)
\(3^{-m}=2187\)
Vì nếu \(k^{-m}\) thì => k = \(\frac{1}{k^m}\)
mà 2187 \(\in N\)
=> Không tìm được m thỏa mãn yêu cầu đề bài.
\(\frac{3^{-m}}{81}=27\Rightarrow3^{-m}=27.81=2187=3^7\)
\(\Rightarrow-m=7\)
\(\Rightarrow m=-7\)
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3^12.(3^4)^11/(3^3)^10.(3^2)^15=3^12.3^44/3^30.3^30=3^56/3^30
=3^17.9^22/3^30.9^15=9^7/3^13=3^14/3^13=3^1=3
giùm nhé bạn
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{3^{-m}}{81}=27\)
\(\Rightarrow3^{-m}=27.81\)
\(\Rightarrow3^{-m}=2187\)
Vì nếu k-m thì =>k=\(\frac{1}{k^m}\)
Mà 2187 \(\in\)N
=>ko tìm đc
![](https://rs.olm.vn/images/avt/0.png?1311)
\(M=\frac{3^6.3^8.5^4-3^{15}.5^{13-9}}{3^{12}.5^6+3^{18}.5^9}.2.\frac{25}{9}=\frac{3^{14}.5^4\left(1-3\right).2.5^2}{3^{12}.5^6\left(1+3^6.5^3\right).3^2}=\frac{-4}{1+3^6.5^3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1
A= \(\frac{81^{10}.3^{17}}{27^{10}.9^{13}}\)
= \(\frac{\left(3^4\right)^{10}.3^{17}}{\left(3^3\right)^{10}.\left(3^2\right)^{13}}\)
= \(\frac{3^{40}.3^{17}}{3^{30}.3^{26}}\)
= \(\frac{3^{57}}{3^{56}}\)= 3
\(\frac{x}{7}\)= \(\frac{-12}{49}\)
=> 49x = (-12) x 7
=> 49x = -84
=> x= \(\frac{-12}{7}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{2^{15}.9^4}{6^3.8^3}\)=\(\frac{2^{15}.\left(3^2\right)^3}{\left(2.3\right)^3.\left(2^3\right)^3}\)=\(\frac{2^{15}.3^6}{2^3.3^3.2^9}\)=\(\frac{2^{15}.3^6}{2^{12}.3^3}\)=\(2^3.3^3\)=8.27=216
\(\frac{3^{-m}}{81}=27\)
\(\frac{3^{-m}}{3^4}=3^3\)
\(3^{-m}=3^3\times3^4\)
\(3^{-m}=3^7\)
\(-m=7\)
\(m=7\)
m = -7 nhể?