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a thì đặt 4 ra ngoài sau đó tự tính theo cách đã học
câu b tương tự
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Câu 11:
(\(\dfrac{11}{4}\). \(\dfrac{-5}{9}\) - \(\dfrac{4}{9}\).\(\dfrac{11}{4}\)).\(\dfrac{8}{33}\)
= \(\dfrac{11}{4}\).(\(\dfrac{-5}{9}\) - \(\dfrac{4}{9}\)). \(\dfrac{8}{33}\)
= \(\dfrac{11}{4}\).(-1).\(\dfrac{8}{33}\)
= - \(\dfrac{2}{3}\)
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\(A=\frac{4}{3}.\frac{4}{7}+\frac{4}{7}.\frac{4}{11}+\frac{4}{11}.\frac{4}{15}+...+\frac{4}{95}.\frac{4}{99}\)
\(\Leftrightarrow\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{15}+...+\frac{1}{95}-\frac{1}{99}\)
\(\Leftrightarrow\frac{1}{3}-\frac{1}{99}\)
\(\Leftrightarrow\frac{32}{99}\)
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=1.3/2^2×2.4/3^2×3.5/4^2×...×29.31/30^2
=1.2.3....29/2.3.4...30×3.4.5....31/2.3.4...30
=1/30×31/2
=31/60
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a, ( 1/2 + 1) . ( 1/3 + 1) . (1/4 + 1) ... ( 1/999 + 1)
= 3/2 . 4/3 . 5/4 . 1000/999
= 1/2 . 1/1 . 1/1 ... 1000/1
= 1000/2
= 500
b, (1/2-1) . (1/3-1) . (1/4-1) ... (1/1000-1)
= -1/2 . (-2)/3 . (-3)/4 ... (-999)/1000
= (-1)/1 . (-1)/1 . (-1)/1 ... (-1)/1000
= (-1)/1000
c, 3/2^2 . 8/3^2 . 15/4^2 ... 99/10^2
= 1.3/2.2 * 2.4/3.3 * 3.5/4.4***9.11/10.10
=( 1.2.3...99).(3.4.5...11)/(2.3.4....10).(2.3.4...10)
= 1.11/2.10
= 11/20