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a: \(\Leftrightarrow4x+\dfrac{3}{4}=2\cdot\dfrac{2}{5}+0.01\cdot10=\dfrac{9}{10}\)
=>4x=3/20
hay x=3/80
b: \(\Leftrightarrow\left|x\right|=4+\dfrac{1}{8}-9=-\dfrac{39}{8}\)(vô lý)
c: 2x(x-2/3)=0
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x-\dfrac{2}{3}=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{2}{3}\end{matrix}\right.\)
d: \(\dfrac{37-x}{x+13}=\dfrac{3}{7}\)
=>259-7x=3x+39
=>-10x=-220
hay x=22
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\sqrt{16}x+\frac{3}{4}=2\sqrt{\frac{4}{25}}+0,01.\sqrt{100}\)
=> \(4x+\frac{3}{4}=2\cdot\frac{2}{5}+0,01\cdot10\)
=> \(4x+\frac{3}{4}=\frac{4}{5}+0,1\)
=> \(4x+\frac{3}{4}=0,9\)
=> \(4x=0,9-\frac{3}{4}\)
=> \(4x=0,15\)
=> \(x=0,15:4=0,0375\)
b) \(\left(x-\frac{2}{5}\right)\left(x+\frac{3}{7}\right)=0\)
=> \(\orbr{\begin{cases}x-\frac{2}{5}=0\\x+\frac{3}{7}=0\end{cases}}\)
=> \(\orbr{\begin{cases}x=\frac{2}{5}\\x=-\frac{3}{7}\end{cases}}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\sqrt{16x}+\frac{3}{4}=2\sqrt{\frac{4}{25}}+0,01\cdot\sqrt{100}\)
=> \(\sqrt{16}\cdot\sqrt{x}+\frac{3}{4}=2\cdot\frac{2}{5}+\frac{1}{100}\cdot10\)
=> \(4\cdot\sqrt{x}+\frac{3}{4}=\frac{4}{5}+\frac{1}{10}\cdot1\)
=> \(4\cdot\sqrt{x}+\frac{3}{4}=\frac{4}{5}+\frac{1}{10}\)
=> \(4\cdot\sqrt{x}+\frac{3}{4}=\frac{8}{10}+\frac{1}{10}=\frac{9}{10}\)
=> \(4\cdot\sqrt{x}=\frac{9}{10}-\frac{3}{4}=\frac{3}{20}\)
=> \(\sqrt{x}=\frac{3}{20}:4\)
=> \(\sqrt{x}=\frac{3}{80}\)
=> \(x=\frac{9}{6400}\)
Vậy x = 9/6400
b) \(2\frac{3}{4}x=3\frac{1}{7}:0,01\)
=> \(\frac{11}{4}x=\frac{22}{7}:\frac{1}{100}\)
=> \(\frac{11}{4}x=\frac{22}{7}\cdot100\)
=> \(\frac{11}{4}x=\frac{2200}{7}\)
=> \(x=\frac{2200}{7}:\frac{11}{4}=\frac{2200}{7}\cdot\frac{4}{11}=\frac{800}{7}\)
Vậy x = 800/7
c) \(\left|x\right|+3^2=2^2+\left(\frac{1}{2}\right)^3\)
=> \(\left|x\right|+9=4+\frac{1}{8}\)
=> \(\left|x\right|+9=\frac{33}{8}\)
=> \(\left|x\right|=\frac{33}{8}-9=-\frac{39}{8}\)
Vì \(\left|x\right|\ge0\)mà \(-\frac{39}{8}< 0\)
=> x không thỏa mãn
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bai 1
a) \(\sqrt{0,36}+\sqrt{0,49}=0,6+0,7=1,3\)
b) \(\sqrt{\frac{4}{9}}-\sqrt{\frac{25}{36}}=\frac{2}{3}-\frac{5}{6}\)
=\(-\frac{1}{6}\)
Bài 2
a)\(x^2=81\Rightarrow\left[{}\begin{matrix}x=9\\x=-9\end{matrix}\right.\)
b) \(\left(x-1\right)^2=\frac{9}{16}\)
\(\Rightarrow\left[{}\begin{matrix}x-1=\frac{3}{4}\\x-1=\frac{-3}{4}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{7}{4}\\x=\frac{1}{4}\end{matrix}\right.\)
c) \(x-2\sqrt{x}=0\Rightarrow\sqrt{x}\left(\sqrt{x}-2\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}\sqrt{x}=0\\\sqrt{x}-2=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=4\end{matrix}\right.\)
d) \(x=\sqrt{x}\Rightarrow x-\sqrt{x}=0\Rightarrow\sqrt{x}\left(\sqrt{x}-1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}\sqrt{x}=0\\\sqrt{x}-1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
1. a) 3+2=5
b) 0,5-0,1=0,4
c) 4/5-1/9=31/45
d) 2-0,6=1,4
2. a) 8-4+3=7
b) 11+5-3=13
c) 3/2-4/6-7-37/6
d) 4+5-6=3