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a) \(x-2=-6\)
\(x=-6+2\)
\(x=-4\)
b) \(15-\left(x-7\right)=-21\)
\(x-7=36\)
\(x=43\)
c) \(4.\left(3x-4\right)-2=18\)
\(4\left(3x-4\right)=20\)
\(3x-4=5\)
\(3x=9\)
\(x=3\)
d) \(\left(3x-6\right)+3=32\)
\(3x-6=29\)
\(3x=29+6\)
\(3x=35\)
\(x=\frac{35}{3}\)
e) \(\left(3x-6\right).3=32\)
\(3x-6=\frac{32}{3}\)
\(3x=\frac{32}{3}+6\)
\(3x=\frac{50}{3}\)
\(x=\frac{50}{9}\)
f) \(\left(3x-6\right):3=32\)
\(3x-6=96\)
\(3x=102\)
\(x=34\)
g) \(\left(3x-6\right)-3=32\)
\(3x-6=35\)
\(3x=41\)
\(x=\frac{41}{3}\)
h) \(\left(3x-2^4\right).7^3=2.7^4\)
\(\left(3x-2^4\right)=2.7=14\)
\(\left(3x-16\right)=14\)
\(3x=14+16=30\)
\(x=10\)
i) \(\left|x\right|=\left|-7\right|\)
\(\left|x\right|=7\)
\(\Rightarrow\orbr{\begin{cases}x=7\\x=-7\end{cases}}\)
k) \(\left|x+1\right|=2\)
\(\Rightarrow\orbr{\begin{cases}x+1=2\\x+1=-2\end{cases}\Rightarrow\orbr{\begin{cases}x=1\\x=-3\end{cases}}}\)
l) \(\left|x-2\right|=3\)
\(\Rightarrow\orbr{\begin{cases}x-2=3\\x-2=-3\end{cases}\Rightarrow\orbr{\begin{cases}x=5\\x=-1\end{cases}}}\)
m) \(x+\left|-2\right|=0\)
\(x+2=0\)
\(x=-2\)
o) \(72-3\left|x+1\right|=9\)
\(3\left|x-1\right|=63\)
\(\left|x-1\right|=21\)
\(\Rightarrow\orbr{\begin{cases}x-1=21\\x-1=-21\end{cases}\Rightarrow\orbr{\begin{cases}x=22\\x=-20\end{cases}}}\)
p) Ta có: \(\left|x-1\right|=3\)
\(\Rightarrow\orbr{\begin{cases}x-1=3\\x-1=-3\end{cases}}\)
mà \(x+1< 0\)
\(\Rightarrow x-1=-3\)
\(\Rightarrow x=-2\)
q) \(\left(x-2\right)\left(x+4\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-2=0\\x+4=0\end{cases}\Rightarrow\orbr{\begin{cases}x=2\\x=-4\end{cases}}}\)
hok tốt!!
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\(a,\left(-2+x\right).\left(3x-6\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}-2+x=0\\3x-6=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2\\x=2\end{cases}\Leftrightarrow}x=2}\)
Vậy ................
\(b,\left(3x+9\right)\left(2x+6\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}3x+9=0\\2x+6=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-3\\x=-3\end{cases}\Leftrightarrow x=-3}\)
Vậy ......................
a)\(\(\left(-2+x\right)\left(3x-6\right)=0\)\)
\(\(\Leftrightarrow\orbr{\begin{cases}-2+x=0\\3x-6=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2\\x=2\end{cases}\Rightarrow}x=2}\)\)
b) cmtt
_Minh ngụy_
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1.Tìm x,y biết:
a,|x-7|=15
|x-7|=15 hoặc |x-7|=-15
Với |x-7|=15
x=15+7
x=22
Với |x-7|=-15
x=(-15)+7
x=-(15+7)
x=-22
c,-|3x-2|=-1
-|3x|=-(1+2)
-|3x|=-3
x=(-3):(-3)
x=-9
d,|x-4|-(-3)=2016
|x-4|=2016-(-3)
|x-4|=2016-3
|x-4|=2013
|x-4|=2013 hoặc |x-4|=-2013
Với |x-4|=2013
x=2013+4
x=2017
Với|x-4|=-2013
x=(-2013)-4
x=-(2013+4)
x=-2017
2 Tìm x biết :
b,x2+x-6=0
x2+x-6=0
x2+x=0+6
x2+x=6
22+2=6
x=2
a) \(\Rightarrow\orbr{\begin{cases}x-7=15\\x-7=-15\end{cases}\Rightarrow\orbr{\begin{cases}x=22\\x=-8\end{cases}}}\)
KL \(\orbr{\begin{cases}x=22\\x=-8\end{cases}}\)
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a: \(\Leftrightarrow x\in\left\{0;-3\right\}\)
b: =>(x-3)(x-5)=0
hay \(x\in\left\{3;5\right\}\)
c: =>x(x-4)=0
hay \(x\in\left\{0;4\right\}\)
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a.\(2^x-2^4.2^7.32=0\)
\(2^x-2^{16}=0\)
\(=>x=16\)
b.\(3^x+3^{x+2}=270\)
\(3^x+3^x.3^2=270\)
\(3^x.10=270\)
\(3^x=27\)
\(=>x=3\)