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\(\frac{1}{2}.2^n+4.2^n=9.2^5\)
\(2^n.\left(\frac{1}{2}.4\right)=288\)
\(2^n.2=288\)
\(2^n=288:2\)
\(2^n=144\)
Suy ra n ko tìm được
Ta có :
\(\frac{1}{2}\cdot2^n+4\cdot2^n=\frac{9}{2}\cdot2^5\)
\(=>\left(\frac{1}{2}+4\right)\cdot2^n=9\cdot2^5\)
\(=>\left(\frac{1}{2}+\frac{8}{2}\right)\cdot2^n=9\cdot2^5\)
\(=>\frac{9}{2}\cdot2^n=\frac{9}{2}\cdot2^5\)
\(=>2^n=2^5\)
\(=>n=5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Ta có: \(\frac{1}{9}\cdot27^n=3^n\)
\(\Leftrightarrow\frac{1}{3^2}\cdot\left(3^3\right)^n=3^n\)
\(\Leftrightarrow3^{3n}=3^{n+2}\)
\(\Rightarrow3n=n+2\)
\(\Rightarrow n=1\)
b) Ta có: \(3^2.3^4.3^n=3^7\)
\(\Rightarrow3^n=3\)
\(\Rightarrow n=1\)
c) Ta có: \(2^{-1}.2^n+4.2^n=9.2^5\)
\(\Leftrightarrow2^n\cdot\frac{9}{2}=9.2^5\)
\(\Rightarrow2^n=2^6\)
\(\Rightarrow n=6\)
d) Ta có: \(32^{-n}.16^n=2048\)
\(\Leftrightarrow\frac{1}{2^{5n}}\cdot2^{4n}=2^{11}\)
\(\Leftrightarrow2^{4n}=2^{5n+11}\)
\(\Rightarrow4n=5n+11\)
\(\Rightarrow n=-11\)
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a, 3600: [ ( 5x + 35 ) : x ] = 50
<=> ( 5x + 35 ) : x = 72
<=> 5x + 35 = 72x
<=> 72x - 5x = 35
<=> 67x = 35
<=> x = 35/67
b, 2n-1 + 4 . 2n = 9 . 25
<=> 2n : 2 + 4 . 2n = 9 . 25
<=> 2n . 1/2 + 4 . 2n = 9 . 25
<=> 2n . ( 1/2 + 4 ) = 9 . 25
<=> 2n . 9/2 = 9 . 25
<=> 2n : 25 = 9 : 9/2
<=> 2n - 5 = 21
<=> n - 5 = 1
<=> n = 6
![](https://rs.olm.vn/images/avt/0.png?1311)
27^n:3^n=9
3^3n:3^n=3^2
3^(3n-n)=3^2
suy ra 3n-n=2
n(3-1)=2
n.2=2
Vậy n=2:2
n=1
còn câu sau cậu tự tính
![](https://rs.olm.vn/images/avt/0.png?1311)
a)1/9.27^n=3^n
3^n=3^n
=>n={0;1;2;3...}
Tích nha ^_^ !!!
2n-1 + 4 . 2n = 9 . 25
=> 2n-1 . ( 1 + 4 . 2 ) = 9 . 25
=> 2n-1 . ( 1 + 8 ) = 9 . 25
=> 2n-1 . 9 = 9 . 25
=> 2n-1 = 25
=> n - 1 = 5
=> n = 6