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a, 10 . 27 - 27 : 9
= 270 - 3
= 263
b, 72 . 33 + 72 . 67
= 72 ( 33 + 67 )
= 72 . 100
= 49 . 100
= 4900
c, 490 - [ ( 128 + 22 ) : 3 . 22 ] - 7
= 490 - ( 150 : 3 . 4 ) - 7
= 490 - ( 50 . 4 ) - 7
= 490 - 200 - 7
= 290 - 7
= 283
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\(a.36+15+64\\ =\left(36+64\right)+15\\ =100+15\\ =115\\ b.12\cdot36+12\cdot64\\ =12\cdot\left(36+64\right)\\ =12\cdot100\\ =1200\\ c.\left(3^2+2^3\cdot5\right):7\\ =\left(9+8\cdot5\right):7\\ =\left(9+40\right):7\\ =49:7\\ =7\)\(\)
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a)
\(11\dfrac{3}{13}-\left(2\dfrac{4}{7}+5\dfrac{3}{13}\right)\)
\(=\dfrac{146}{13}-\left(\dfrac{18}{7}+\dfrac{68}{13}\right)\)
\(=\dfrac{146}{13}-\dfrac{18}{7}-\dfrac{68}{13}\)
\(=\left(\dfrac{146}{13}-\dfrac{68}{13}\right)-\dfrac{18}{7}\)
\(=6-\dfrac{18}{7}\)
\(=\dfrac{24}{7}\)
b)
\(\dfrac{2}{7}\times5\dfrac{1}{4}-\dfrac{2}{7}\times3\dfrac{1}{4}\)
\(=\dfrac{2}{7}\times\dfrac{21}{4}-\dfrac{2}{7}\times\dfrac{13}{4}\)
\(=\dfrac{2}{7}\times\left(\dfrac{21}{4}-\dfrac{13}{4}\right)\)
\(=\dfrac{2}{7}\times2\)
\(=\dfrac{4}{7}\)
\(a,11\dfrac{3}{13}-\left(2\dfrac{4}{7}+5\dfrac{3}{13}\right)\)
\(=\dfrac{146}{13}-\left(\dfrac{18}{7}+\dfrac{68}{13}\right)\)
\(=\dfrac{146}{13}-\dfrac{68}{13}-\dfrac{18}{7}\)
\(=6-\dfrac{18}{7}\)
\(=\dfrac{24}{7}\)
\(b,\dfrac{2}{7}\times5\dfrac{1}{4}-\dfrac{2}{7}\times3\dfrac{1}{4}\)
\(=\dfrac{2}{7}\times\dfrac{21}{4}-\dfrac{2}{7}\times\dfrac{13}{4}\)
\(=\dfrac{2}{7}\times\left(\dfrac{21}{4}-\dfrac{13}{4}\right)\)
\(=\dfrac{2}{7}\times2\)
\(=\dfrac{4}{7}\)
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= -5 / 7 x ( 2 / 11 + 9 / 11) + 12/7
= -5/7 x 1 + 12/7
= -5/7 + 12/7
= 1
b, = ( 9/4 x 105 - 9/4 x 101) : 3/2 - 64 x ( 1/4 - 3/4)
= [ 9/4 x ( 105 - 101)] : 3/2 -64 x -1/2
= 9/4 x 4 : 3 /2 - (-32)
= 9 : 3/2 + 32
= 18/3 +32
=
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\(B=7^5:7^3-6^2\cdot2+2^3\cdot2^2\)
\(B=7^2-36\cdot2+2^5\)
\(B=49-36\cdot2+32\)
\(B=49-72+32\)
\(B=9\)
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`a,5 xx (-7)+(-2) xx (-5)`
`=5 xx (-7)+5 xx 2`
`= 5 xx (2-7)`
`=5 xx (-5)`
`=-25`
`b,5 xx (-9)+(-2) xx 3`
`=3 xx (-15)+3 xx (-2)`
`=3 xx (-15-2)`
`=3 xx (-17)`
`=-51`
`c,6 xx (-5)^2+3 xx (-15)`
`=2 xx 3 xx 25+3 xx (-15)`
`=3 xx 75-3 xx 15`
`=3 xx (75-15)`
`=3 xx 60`
`=180`
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\(3D=\frac{6}{1.7}+\frac{6}{7.13}+....+\frac{6}{601.607}\)
a)\(315-64:2^3\)
\(=315-2^6:2^3\)
\(=315-8=307\)
b)\(7^2.33+7^2.67\)
\(=7^2\left(33+67\right)\)
\(=7^2.100=4900\)
a) \(315-64\div2^3=315-2^6\div2^3=315-2^{6-3}=315-2^3=315-8=307\)
b) \(7^2.33+7^2.67=7^2.\left(33+67\right)=7^2.100=49.100=4900\)