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x4 + 64 = (x4 + 16x2 + 64) - 16x2 = (x2 + 8)2 - (4x)2 = (x2 - 4x + 8).(x2 + 4x + 8)
Ta có
x4 + 64
= (x4 + 16x2 + 64) - 16x2
= (x2 + 8)2 - (4x)2
= (x2 - 4x + 8).(x2 + 4x + 8)
hok tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có:
x^4 + 64 = (x²)² + 8² + 2x².8 - 2.x².8
= (x² + 8)² - (4x)²
= (x² - 4x + 8)(x² + 4x + 8)
Ta có:
x^4 + 64 = (x²)² + 8² + 2x².8 - 2.x².8
= (x² + 8)² - (4x)²
= (x² - 4x + 8)(x² + 4x + 8)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có:
x^4 + 64 = (x²)² + 8² + 2x².8 - 2.x².8
= (x² + 8)² - (4x)²
= (x² - 4x + 8)(x² + 4x + 8)
k nhoa
Ta có:
x^4 + 64 = (x²)² + 8² + 2x².8 - 2.x².8
= (x² + 8)² - (4x)²
= (x² - 4x + 8)(x² + 4x + 8)
k nhoa
![](https://rs.olm.vn/images/avt/0.png?1311)
1) \(64-y^2=8^2-y^2=\left(8-y\right)\left(8+y\right)\)
2) \(81-x^2=9^2-x^2=\left(9-x\right)\left(9+x\right)\)
3) \(100-a^2=10^2-a^2=\left(10-a\right)\left(10+a\right)\)
4) \(144-b^2=12^2-b^2=\left(12-b\right)\left(12+b\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x^4+64\)
\(=\left(x^2\right)^2+8^2+2x^2.8-2x^2.8\)
\(=\left(x^2+8\right)^2-\left(4x^2\right)\)
\(=\left(x^2-4x+8\right)\left(x^2+4x+8\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có : \(x^3-64\)
\(=x^3-4^3\)
Áp dung hằng dẳng thức : \(a^3-b^3=\left(a-b\right)\left(a^2+ab+b^2\right)\)
\(\Rightarrow x^3-4^3=\left(x-4\right)\left(x^2+4x+4^2\right)\)
\(x^3\)\(-64\)\(=x^3\)\(-4^3\)=\(\left(x-4\right)\)\(\left(x^2+4x+16\right)\)
câu này lên google
\(x^{64}+x^{32}+1\)
\(=\left(x^{32}\right)^2+2x^{32}+1+x^{32}-2x^{32}\)
\(=\left(x^{32}+1\right)^2-x^{32}\)
\(=\left(x^{32}+1\right)^2-\left(x^{16}\right)^2\)
\(=\left(x^{32}+1-x^{16}\right).\left(x^{32}+1+x^{16}\right)\)