![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(n_{Mg}=\dfrac{1,2}{24}=0,05\left(mol\right)\\
pthh:Mg+2HCl\rightarrow MgCl_2+H_2\)
0,05 0,05
\(n_{CuO}=\dfrac{8}{80}=0,1\left(mol\right)\)
\(pthh:CuO+H_2\underrightarrow{t^o}Cu+H_2O\)
\(LTL:0,1>0,05\)
=> CuO dư
theo pthh: \(n_{CuO\left(p\text{ư}\right)}=n_{Cu}=n_{H_2}=0,05\left(mol\right)\)
\(\Rightarrow m_{Cu}=0,05.64=3,2\left(g\right)\)
\(\Rightarrow m_{CuO\left(d\right)}=\left(0,1-0,05\right).80=4\left(g\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(n_{H_2}=\dfrac{0,224}{22,4}=0,01\left(mol\right)\\
pthh:2R+2H_2O\rightarrow2ROH+H_2\)
0,02 0,01 (mol)
\(\Rightarrow M_R=0,78:0,02=39\left(\dfrac{g}{mol}\right)\)
mà R hóa trị I => R là K
Số mol chất tan có trong 80 gam dung dịch CuSO4 30% là Mọi người giải chị tiết hộ mình , mình cảm ơn
![](https://rs.olm.vn/images/avt/0.png?1311)
$m_{CuSO_4}=80.30\%=24(g)$
$\to n_{CuSO_4}=\dfrac{24}{160}=0,15(mol)$
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Magie cacbonat \(\xrightarrow{t^o}\) Magie oxit + Cacbon đioxit
b) \(m_{MgCO_3} = m_{MgO} + m_{CO_2}\)
c)
\(m_{MgCO_3} = 60 + 66 = 126(kg)\\ \Rightarrow \%m_{MgCO_3} = \dfrac{126}{150}.100\% = 84\%\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(\left\{{}\begin{matrix}p+e+n=52\\p=e\\p+e-n=16\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2n=36\\p=e\\p+e+n=52\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}n=18\\p=e=17\end{matrix}\right.\)
1/ \(2HCl+K_2CO_3\rightarrow H_2O+2KCl+CO_2\uparrow\)
2/ \(HCl+KHCO_3\rightarrow H_2O+KCl+CO_2\uparrow\)
3/ \(2HCl+CaCO_3\rightarrow H_2O+CaCl_2+CO_2\uparrow\)
4/ \(2HCl+MgCO_3\rightarrow H_2O+MgCl_2+CO_2\uparrow\)
5/ \(2HCl+Ca\left(HCO_3\right)_2\rightarrow2H_2O+CaCl_2+2CO_2\uparrow\)
6/ \(HCl+NaHSO_3\rightarrow H_2O+NaCl+SO_2\uparrow\)
\(2HCl+K_2CO_3\rightarrow2KCl+CO_2+H_2O\\ 2HCl+CaCO_3\rightarrow CaCl_2+CO_2+H_2O\\ 2HCl+MgCO_3\rightarrow MgCl_2+CO_2+H_2O\\ 2HCl+Ca\left(HCO_3\right)_2\rightarrow2CaCl_2+2CO_2+2H_2O\\ HCl+NaHSO_3\rightarrow NaCl+SO_2+H_2O\)