Câu hỏi của 18 Nguyễn Hà Linh

Question

Mọi ng giải giúp mik . mik cần g.ấ.p

Vô danh · Accepted Answer

$g,\dfrac{-3}{31}+\dfrac{-6}{17}+\dfrac{1}{25}+\dfrac{-28}{31}+\dfrac{-11}{17}+\dfrac{-1}{5}\
=\left(\dfrac{-3}{31}+\dfrac{-28}{31}\right)+\left(\dfrac{-6}{17}+\dfrac{-11}{17}\right)+\left(\dfrac{1}{25}+\dfrac{-5}{25}\right)\
=\dfrac{-31}{31}+\dfrac{-17}{17}+\dfrac{-1}{25}\
=\left(-1\right)+\left(-1\right)+\dfrac{-4}{25}\
=-\dfrac{54}{25}\
h,\dfrac{-4}{12}+\dfrac{18}{45}+\dfrac{-6}{9}+\dfrac{-21}{35}+\dfrac{6}{30}\
=\dfrac{-1}{2}+\dfrac{2}{5}+\dfrac{-2}{3}+\dfrac{-3}{5}+\dfrac{1}{5}\
=\dfrac{-1}{2}+\dfrac{-2}{3}+\left(\dfrac{2}{5}+\dfrac{-3}{5}+\dfrac{1}{5}\right)\
=\dfrac{-3}{6}+\dfrac{-4}{6}+\dfrac{0}{5}\
=\dfrac{-7}{6}+0\
=-\dfrac{7}{6}$Câu trả lời: $g,\dfrac{-3}{31}+\dfrac{-6}{17}+\dfrac{1}{25}+\dfrac{-28}{31}+\dfrac{-11}{17}+\dfrac{-1}{5}\
=\left(\dfrac{-3}{31}+\dfrac{-28}{31}\right)+\left(\dfrac{-6}{17}+\dfrac{-11}{17}\right)+\left(\dfrac{1}{25}+\dfrac{-5}{25}\right)\
=\dfrac{-31}{31}+\dfrac{-17}{17}+\dfrac{-1}{25}\
=\left(-1\right)+\left(-1\right)+\dfrac{-4}{25}\
=-\dfrac{54}{25}\
h,\dfrac{-4}{12}+\dfrac{18}{45}+\dfrac{-6}{9}+\dfrac{-21}{35}+\dfrac{6}{30}\
=\dfrac{-1}{2}+\dfrac{2}{5}+\dfrac{-2}{3}+\dfrac{-3}{5}+\dfrac{1}{5}\
=\dfrac{-1}{2}+\dfrac{-2}{3}+\left(\dfrac{2}{5}+\dfrac{-3}{5}+\dfrac{1}{5}\right)\
=\dfrac{-3}{6}+\dfrac{-4}{6}+\dfrac{0}{5}\
=\dfrac{-7}{6}+0\
=-\dfrac{7}{6}$

18 Nguyễn Hà Linh · Answer

Nhưng còn câu f nx bạn nhé Câu trả lời: Nhưng còn câu f nx bạn nhé

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