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\(75^{20}=\left(3.5^2\right)^{20}=3^{20}.5^{40}\)
\(45^{10}.25^{15}=\left(3^2.5\right)^{10}.\left(5^2\right)^{15}=3^{20}.5^{10}.5^{30}=3^{20}.5^{40}\)
Vậy ........
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có :
\(75^{10}.75^{10}=\left(5^{10}.3^{10}.3^{10}\right).\left(5^{10}.5^{10}.5^{10}\right)\)
\(75^{10}.75^{10}=\left(5^{10}.5^{10}.3^{10}\right).\left(5^{10}.5^{10}.3^{10}\right)\)
\(75^{10}.75^{10}=75^{10}.75^{10}\)
Vì vậy : \(75^{20}=45^{10}.5^{30}\)
\(75^{20}=3^{20}.5^{40}\)
\(45^{10}.5^{30}=3^{20}.5^{40}\)
Do đó:\(75^{20}=45^{10}.5^{30}\)(đpcm)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: 7520 = (52 . 3)20 = 540 . 320
4510 . 2515 = (32 . 5)10 . (52)15 = 320 . 510 . 530 = 320 . 540
=> 7520 = 4510 . 2515 (= 320 . 540)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có
\(45^{10}.5^{30}=\left(3^2.5\right)^{10}.\left(5^2\right)^{15}=3^{20}.\left(5^2\right)^5.25^{15}=3^{20}.25^5.25^{15}=3^{20}.25^{20}=75^{20}\)
Ta có:7520=(52.3)20=540.320
4510.530=(5.32)10.530=510.320.530=540.320
Do:540.320=540.320
=>7520=540.320
Vậy....
![](https://rs.olm.vn/images/avt/0.png?1311)
a. 128 . 324 = 48 . 38 . 324 = (22)8 . 332 = 216 . (32)16 = 216 . 916 = 1816
=> đpcm
b. 4510 . 2515 = 510 . 910 . 2515 = 510 . 910 . (52)15 = 510 . 910 . 530 = 540 . (32)10 = (52)20 . 320 = 2520 . 320 = 7520
=> đpcm
Ủng hộ mk nha ^_-
a)Ta có:
\(12^8.3^{24}=\left(2^2\right)^8.3^8.3^{24}=2^{16}.3^{32}\) (1)
\(18^{16}=2^{16}.\left(3^2\right)^{16}=2^{16}.3^{32}\)(2)
Từ (1) và (2) => \(12^8.3^{24}=18^{16}\)(đpcm)
b)Ta có:
\(75^{20}=3^{20}.\left(5^2\right)^{20}=3^{20}.5^{40}\) (1)
\(45^{10}.25^{15}=\left(3^2\right)^{10}.5^{10}.\left(5^2\right)^{15}=3^{20}.5^{10}.5^{30}=3^{20}.5^{40}\) (2)
Từ (1) và (2) => \(75^{20}=45^{10}.25^{15}\) (đpcm)
7520=4510.2515 <=> (25.3)20=(5.9)10.(52)15 <=>540.320=510.320.530 <=> 540.320= 540.320
quá dễ
\(75^{20}=\left(3\cdot5^2\right)^{20}=3^{20}\cdot5^{40}\)
\(45^{10}\cdot25^{15}=\left(3^2\cdot5\right)^{10}\cdot\left(5^2\right)^{15}=3^{20}\cdot5^{40}\)
Thi trổ tài ở đâu vậy