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\(e,\left(x-2\right).3-270:45=120\)
\(\Rightarrow\left(x-2\right).3-6=120\)
\(\Rightarrow\left(x-2\right).3=126\)
\(\Rightarrow x-2=42\)
\(\Rightarrow x=44\)
Bài làm
a) 16 . 34 + 66 . 16 - 72
= 16 . ( 34 + 16 ) - 72
= 16 . 80 - 72
= 1280 - 72
= 1208
b) 4,25 . 58,47 + 125 + 41,53 . 4,25
= 4,25 . ( 58,47 + 41,53 ) + 125
= 4,25 . 100 + 125
= 425 + 125
= 550
c) x : 15 + 42 = 15 + 25 . 8
x : 15 + 42 = 15 + 200
x : 15 + 42 = 215
x : 15 = 215 - 42
x : 15 = 173
x = 173 . 15
x = 188
Vậy x = 188
~ Hai câu cuối làm nốt nha, hết thời gian cho một câu hỏi r. ~
# Học tốt #
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bài 2 tìm x
a,106- ( x+ 7) =9
x+7 = 106 - 9
x+7 = 107
x= 107 - 7
x=100
b, 2 x ( x+ 4) + 5 =65
2 x (x+4) = 65 - 5
2 x (x+4) = 60
x+4 = 60:2
x+4= 30
x= 30 - 4
x=26
c, (16x x -32) x 45=0
16 x X - 32 = 0: 45
16 x X - 32 =0
16 x X = 0 + 32
16 x X = 32
X= 32:16
X=2
d, x+4 x x = 100 : 5
X + 4 x X = 20
(1+4) x X = 20
5 x X = 20
X= 20:5
X=4
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Lời giải:
$25.6+5.5.29-45.5=25.6+25.29-9.25$
$=25(6+29-9)=25.26=650$
![](https://rs.olm.vn/images/avt/0.png?1311)
1: =>x=8-35=-27
2: =>15-4+x=6
=>x+11=6
hay x=-5
3: =>-30+25-x=-1
=>x+5=1
hay x=-4
4: =>x-(-13)=-8
=>x+13=-8
hay x=-21
5: =>x-29-17+38=-9
=>x-8=-9
hay x=-1
![](https://rs.olm.vn/images/avt/0.png?1311)
Giải:
a) \(-5< x< 1\)
\(\Leftrightarrow x\in\left\{-4;-3;-2;-1;0\right\}\)
Vậy ...
b) \(\left|x\right|< 3\)
\(\Leftrightarrow\left|x\right|\in\left\{0;1;2\right\}\) (Vì \(\left|x\right|\ge0;\forall x\))
\(\Leftrightarrow\left|x\right|\in\left\{0;-1;1;-2;2\right\}\)
Vậy ...
c) \(\left(x-3\right)\left(x-5\right)< 0\)
\(\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x-3>0\\x-5< 0\end{matrix}\right.\\\left\{{}\begin{matrix}x-3< 0\\x-5>0\end{matrix}\right.\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x>3\\x< 5\end{matrix}\right.\\\left\{{}\begin{matrix}x< 3\\x>5\end{matrix}\right.\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}3< x< 5\\3>x>5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4\\x\in\varnothing\end{matrix}\right.\)
Vậy ...
d) \(2x^2-3=29\)
\(\Leftrightarrow2x^2=29+3=32\)
\(\Leftrightarrow x^2=\dfrac{32}{2}=16\)
\(\Leftrightarrow x=\pm4\)
Vậy ...
e) \(-6x-\left(-7\right)=25\)
\(\Leftrightarrow-6x+7=25\)
\(\Leftrightarrow-6x=25-7=18\)
\(\Leftrightarrow x=-\dfrac{18}{6}=-3\)
Vậy ...
5x+1- 5x=100.2529
5x.(5-1) = 100.2529
5x.4=100.2529
5x=100.2529: 4
5x=25.2529
5x=2530
5x= (52)30
5x=560
=> x =60
#yêuToán
5x + 1 - 5x = 100.2529
=> 5x.5 - 5x = 4.52.(52)29
=> 5x(5 - 1) = 4.52.558
=> 5x .4 = 4.560
=> 5x = 4.560 : 4
=> 5x = 560
=> x = 60