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\(\Leftrightarrow-\dfrac{2}{5}\left(4x-3\right)^2=-\dfrac{5}{18}\)
\(\Leftrightarrow\left(4x-3\right)^2=\dfrac{25}{36}\)
\(\Leftrightarrow4x-3\in\left\{\dfrac{5}{6};-\dfrac{5}{6}\right\}\)
hay \(x\in\left\{\dfrac{23}{24};\dfrac{13}{24}\right\}\)
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\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-3\\x=2\end{matrix}\right.\)
\(\Leftrightarrow3\left(x-2\right)\left(3-x\right)\left(3+x\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=3\\x=-3\\x=2\end{matrix}\right.\)
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\(5^{x+1}=125\)
\(5^{x+1}=5^3\)
\(x+1=3\)
\(x=2\)
b, \(5^{2x-3}-2.5^2=5^2.3\)
\(5^{2x-3}=5^2.\left(3+2\right)\)
\(5^{2x-3}=5^3\)
\(2x-3=3\)
\(x=3\)
c, \(2^x=32\)
\(2^x=2^5\)
\(x=5\)
Chúc em học tốt.
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Trả lời :
56 : 54 + 23 . 22 - 225 : 152
= 56 - 4 + 23 + 2 - 152 : 152
= 52 + 25 - 1
= 25 + 32 - 1
= 56
\(5x\left(x^2+1\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}5x=0\\x^2+1=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x^2=-1\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x\in\varnothing\end{cases}}\)