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![](https://rs.olm.vn/images/avt/0.png?1311)
= 35.47 + 35.32 - 35.47 - 47.32
= 32.(35 - 47)
= 32.(-15) = -480
![](https://rs.olm.vn/images/avt/0.png?1311)
35.47+35.32-47.35+47.32
(35.47 - 47 . 35 ) + 32 . (35 + 47 )
0 + 32 . 82
= 2624
dễ mà bạn, cứ phá ngoặc ra rồi kết hợp vào và sử dụng 1 số nhân một tông hoặc một hiệu gì đó
![](https://rs.olm.vn/images/avt/0.png?1311)
a, 35.47+35.47-47.35+47.32
=(35.47-47.35)+ 35.47+47.32
=47.(35+32)
=47.67
=3149
b,-(689-275)+(-275+689)
=-689+275+(-275)+689
=(-689+689)+[275+(-275)]
=0
K mình nha
a) 35(47+32)-47(35+32)
=35.47+32-47.35+32
=32[35.47-47.35]
=32[35(47-470]
=32(35.0)
=32.0=0
![](https://rs.olm.vn/images/avt/0.png?1311)
1/3+1/30+1/32+1/35+1/45 +1/47 +1/50 < 7/14
1/3+1/30+1/32+1/35+1/45 +1/47 +1/50 <1/14 +1/14 +1/14 +1/14 +1/14 +1/14 +1/14
dù 1/3>1/14 nhưng :1/30<1/14 1/32<1/14 ;1/35<1/14 ;1/45<1/14 ;1/47<1/14 ;1/50<1/14
nên: 1/3+1/30+1/32+1/35+1/45 +1/47 +1/50 < 1/2
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(\frac{1}{32}< \frac{1}{30};\frac{1}{35}< \frac{1}{30}\)
=> \(\frac{1}{30}+\frac{1}{32}+\frac{1}{35}< \frac{1}{30}+\frac{1}{30}+\frac{1}{30}=\frac{1}{10}\)
\(\frac{1}{47}< \frac{1}{45};\frac{1}{50}< \frac{1}{45}\)
=> \(\frac{1}{45}+\frac{1}{47}+\frac{1}{50}< \frac{1}{45}+\frac{1}{45}+\frac{1}{45}=\frac{3}{45}=\frac{1}{15}\)
=> \(\frac{1}{3}+\frac{1}{30}+\frac{1}{32}+\frac{1}{35}+\frac{1}{45}+\frac{1}{50}< \frac{1}{3}+\frac{1}{10}+\frac{1}{15}=\frac{1}{2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) (135 - 35) . (-37) + 37 . (-42 - 58)
= 100 . 0 . (-100)
= 0
b) -65 . (87 - 17) - 87 . (17 - 65)
= -65 . 70 - 87 . (-48)
= -4550 - 135
= -4415
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có : 1/3 < 1/2
1/30 < 1/2
1/32 < 1/2
1/35 < 1/2
1/45 < 1/2
1/47 < 1/2
1/50 < 1/2
=> 1/3 + 1/30 + 1/32 + 1/35 + 1/45 + 1/47 + 1/50 < 1/2
@Ác Quỷ Bóng Tối
\(\dfrac{1}{3}+\dfrac{1}{30}+\dfrac{1}{32}+\dfrac{1}{35}+\dfrac{1}{45}+\dfrac{1}{47}+\dfrac{1}{50}< \dfrac{1}{2}\)
\(\Rightarrow\)\(\dfrac{1}{3}+\dfrac{1}{30}+\dfrac{1}{32}+\dfrac{1}{35}+\dfrac{1}{45}+\dfrac{1}{47}+\dfrac{1}{50}< \dfrac{7}{14}\)
\(\Rightarrow\dfrac{1}{3}+\dfrac{1}{30}+\dfrac{1}{32}+\dfrac{1}{35}+\dfrac{1}{45}+\dfrac{1}{47}+\dfrac{1}{50}< \dfrac{1}{14}+\dfrac{1}{14}+\dfrac{1}{14}+\dfrac{1}{14}+\dfrac{1}{14}+\dfrac{1}{14}+\dfrac{1}{14}\)
Dù \(\dfrac{1}{3}>\dfrac{1}{14}\) nhưng:
\(\dfrac{1}{30}< \dfrac{1}{14}\)
\(\dfrac{1}{32}< \dfrac{1}{14}\)
\(\dfrac{1}{35}< \dfrac{1}{14}\)
\(\dfrac{1}{45}< \dfrac{1}{14}\)
\(\dfrac{1}{47}< \dfrac{1}{14}\)
\(\dfrac{1}{50}< \dfrac{1}{14}\)
\(\Rightarrow\) \(\dfrac{1}{3}+\dfrac{1}{30}+\dfrac{1}{32}+\dfrac{1}{35}+\dfrac{1}{45}+\dfrac{1}{47}+\dfrac{1}{50}< \dfrac{1}{2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\text{35 + (–47) – |–12|}\)
\(=-12-12\)
\(=-24\)
\(\text{(–15) – 70 : (–14) + (–32) . (–2)}\)
\(=-15+5+64\)
\(=-10+64\)
\(=54\)
\(\text{ 15 – 12 . (-3)^2 – 135 : |–15|}\)
\(=15-12.9-135:15\)
\(=15-108-9\)
\(=-102\)
Tính hợp lý:
\(\text{ –24 . 78 + 24(–35) – 24(–13)}\)
\(=24.\left(-78+\left(-35\right)-\left(-13\right)\right)\)
\(=24.\left(-100\right)\)
\(=-2400\)
học tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
x - ( 17 - x ) = x + 3
<=> 2x - 17 = x + 3
<=> x = 20
Vậy x = 20
- ( x + 12 ) + 35 = - 47
<=> - x - 12 = - 47 -35
<=> x = 47 + 35 - 12
<=> x = 60
Vậy x = 60
15 - ( x + 32 ) = - 11
<=> 15 - x - 32 = - 11
<=> - x - 17 = - 11
<=> - x = - 11 + 17 = 6
<=> x = - 6
Vậy x = - 6
K chắc lắm
a)\(x-\left(17-x\right)=x+3\)
\(\Leftrightarrow x-17+x=x+3\)
\(\Leftrightarrow x+x-x=17+3\)
\(\Leftrightarrow x=20\)
b)\(-\left(x+12\right)+35=-47\)
\(\Leftrightarrow-x-12+35=-47\)
\(\Leftrightarrow-x=-47+12-35\)
\(\Leftrightarrow-x=-70\)
\(\Leftrightarrow x=70\)
c)\(15-\left(x+32\right)=-11\)
\(\Leftrightarrow15-x-32=-11\)
\(\Leftrightarrow-x=-11-15+32\)
\(\Leftrightarrow-x=6\)
\(\Leftrightarrow x=-6\)
35(47+32)-47(35+32)=35.47+35.32-35.47-47.32=35.32-47.32= -12.32= -384