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\(A=\frac{1\cdot2+2\cdot4+3\cdot6+4\cdot8+5\cdot10+6\cdot12}{3\cdot4+6\cdot8+9\cdot12+12\cdot16+15\cdot20+18\cdot24}\)
\(A=\frac{2\cdot3\left[1\cdot2\right]+2\cdot3\left[2\cdot4\right]+2\cdot3\left[3\cdot6\right]+2\cdot3\left[4\cdot8\right]+2\cdot3\left[5\cdot10\right]}{3\cdot4\left[3\cdot4+6\cdot8+9\cdot12+12\cdot16+15\cdot20\right]}\)
\(A=\frac{\left[3\cdot4+6\cdot8+9\cdot12+12\cdot16+15\cdot20\right]}{2\cdot3\left[3\cdot4+6\cdot8+9\cdot12+12\cdot16+15\cdot20\right]}=\frac{1}{2\cdot3}=\frac{1}{6}\)
\(\frac{7}{3}\)\(+\frac{1}{2}\)\(+\frac{-3}{70}\)\(=\frac{293}{105}\)
\(\frac{5}{12}\)\(+\frac{3}{-16}\)\(+\frac{3}{4}\)\(=\frac{47}{48}\)
\(\frac{5}{3}\)\(+\left(7+\frac{-5}{3}\right)=\frac{5}{3}\)\(+\frac{-5}{3}\)\(+7=0+7=7\)
\(\frac{-7}{31}\)\(+\left(\frac{24}{17}+\frac{7}{31}\right)=\left(\frac{-7}{31}+\frac{7}{31}\right)+\frac{24}{17}=0+\frac{24}{17}\)\(=\frac{24}{17}\)
\(\frac{3}{7}\)\(+\left(\frac{-1}{5}+\frac{-3}{7}\right)=\left(\frac{3}{7}+\frac{-3}{7}\right)+\frac{-1}{5}\)\(=0+\frac{-1}{5}\)\(=\frac{-1}{5}\)
Nếu được cho mình xin 1 k đúng ^_^
1-2+3-4+5-6...+2015-2016
= (1 - 2) + (3 - 4) + (5 - 6) + ... + (2015 - 2016)
= -1 + (-1) + (-1) + ... + (-1) có 1008 số -1
= -1.1008
= -1008
1 - 2 + 3 - 4 + 5 - 6 + ... + 2015 - 2016
= ( 1- 2) + (3 - 4) + ( 5 - 6 ) + .... + (2015 - 2016 )
= ( -1 ) + (-1) + ( -1 ) + ..... + (-1) [ Có 1008 số ( -1 ) ]
= ( -1 ) . 1008
= -1008
( 2x+ 3 ) : 22 = 231 - 9 = 222
2x + 3 = 222 . 22 = 4884
2x = 4884 - 3 = 4881
x = 4881 : 2 = 2440,5
