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a) \(\left|x\right|+2=9\Leftrightarrow\left|x\right|=7\Leftrightarrow x=\pm7\).
b) \(\left|x-4\right|=1\Leftrightarrow\orbr{\begin{cases}x-4=-1\\x-4=1\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=3\\x=5\end{cases}}\).
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\(a.\frac{8}{7}+\frac{4}{7}\times\left(-\frac{6}{11}\right)-\frac{4}{7}\times\frac{5}{11}\)
\(=\frac{8}{7}+\frac{4}{7}\left(-\frac{6}{11}-\frac{5}{11}\right)\)
\(=\frac{8}{7}+\frac{4}{7}.\left(-1\right)\)
\(=\frac{8}{7}-\frac{4}{7}\)
\(=\frac{4}{7}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Mình chỉ giúp đc vài câu thôi xin lỗi nhé !
a, 2x - 7 = -11
2x = -11 + 7
2x = -18
x = -18 : 2
x = -9
a) 2x - 7 = -11
2x=-11+7
2x=-4
x=-4:2
x=-2
Vậy x=-2
b) 5 + 3x = |-11|
5+3x=11
3x=11-5
3x=6
x=6:3
x=2
Vậy x=2
c) | 2x - 3 | - | 5 | = | -11 | - 3
|2x-3|-5=11-3
|2x-3|=11-3+5
|2x-3|=14
* 2x-3=14 * 2x-3=-14
2x=14+3 2x=-14+3
2x=17 2x=-11
x=17/2 x=-11/2
Vậy x=17/2 hoặc x=-11/2
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`[x-3]/5=[2x-6]/10`
`[2(x-3)]/10=[2x-6]/10`
`2x-6=2x-6`
`2x-2x=-6+6`
`0x=0` (LĐ)
Vậy `x in RR`
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,-\dfrac{12}{16}-\left(\dfrac{3}{4}-x\right)=-\dfrac{5}{3}\)
\(\dfrac{3}{4}-x=-\dfrac{12}{16}-\left(-\dfrac{5}{3}\right)\)
\(\dfrac{3}{4}-x=\dfrac{11}{12}\)
\(x=\dfrac{3}{4}-\dfrac{11}{12}\)
\(x=-\dfrac{1}{6}\)
\(b,x-\dfrac{3}{7}:\dfrac{9}{14}=-\dfrac{7}{3}\)
\(x-\dfrac{3}{7}=-\dfrac{7}{3}\times\dfrac{9}{14}\)
\(x-\dfrac{3}{7}=-\dfrac{3}{2}\)
\(x=-\dfrac{3}{2}+\dfrac{3}{7}\)
\(x=-\dfrac{15}{14}\)
\(c,-\dfrac{3}{4}x+\dfrac{5}{8}x=\dfrac{1}{3}\)
\(\left(-\dfrac{3}{4}+\dfrac{5}{8}\right)x=\dfrac{1}{3}\)
\(-\dfrac{1}{8}x=\dfrac{1}{3}\)
\(x=\dfrac{1}{3}:\left(-\dfrac{1}{8}\right)\)
\(x=-\dfrac{8}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{3\hept{59x+0,}\left(72\right)}{8}\)hok tốt nha
3 . ( x + 4 ) - 1 = 11
3. ( x + 4 ) = 11 + 1
3. ( x + 4 ) = 12
( x + 4 ) = 12 : 3
( x + 4 ) = 4
x = 4 - 4
x = 0
Nhớ k nha