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a, \(\frac{12\times3\times4}{24\times25\times26}\)=\(\frac{12\times3\times2\times2}{12\times2\times25\times13\times2}\)=\(\frac{1\times3\times1\times1}{1\times1\times25\times13\times1}\)=\(\frac{3}{25\times13}\)=\(\frac{3}{325}\)
b, \(\frac{5}{8}\)\(\times\)\(\frac{3}{7}\)\(+\)\(\frac{5}{8}\)\(\times\)\(\frac{4}{7}\)= \(\frac{5}{8}\)\(\times\)\((\)\(\frac{3}{7}\)\(+\)\(\frac{4}{7}\)\()\)
= \(\frac{5}{8}\)\(\times\)\(1\)=\(\frac{5}{8}\)
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a.1/4 +3/8 +5/16=15/16
b, 3/5 - 1/3 -1/6=1/10
c, 4/7 *5/8 *7/12=5/24
d. 25/28 : 15/24 * 6/7=60/49
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\(a,=\frac{7-1}{1.3.7}+\frac{9-3}{3.7.9}+\frac{13-7}{7.9.13}+\frac{15-9}{9.13.15}\)\(+\frac{19-13}{13.15.19}\)
\(=\frac{1}{1.3}-\frac{1}{3.7}+\frac{1}{3.7}-\frac{1}{7.9}+\frac{1}{7.9}-\frac{1}{9.13}+\frac{1}{9.13}-\frac{1}{13.15}+\frac{1}{13.15}-\frac{1}{15.19}\)
\(=\frac{1}{1.3}-\frac{1}{15.19}=\frac{95}{285}-\frac{1}{285}=\frac{94}{285}\)
\(b,=\frac{1}{6}.\left(\frac{6}{1.3.7}+\frac{6}{3.7.9}+\frac{6}{7.9.13}+\frac{6}{9.13.15}+\frac{6}{13.15.19}\right)\)
làm giống như trên
\(c,=\frac{1}{8}.\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{48.49.50}\right)\)
\(=\frac{1}{16}.\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+\frac{2}{3.4.5}+...+\frac{2}{48.49.50}\right)\)
\(=\frac{1}{16}.\left(\frac{3-1}{1.2.3}+\frac{4-2}{2.3.4}+\frac{5-3}{3.4.5}+...+\frac{50-48}{48.49.50}\right)\)
\(=\frac{1}{16}.\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{48.49}-\frac{1}{49.50}\right)\)
\(=\frac{1}{16}.\left(\frac{1}{2}-\frac{1}{2450}\right)=\frac{1}{16}.\left(\frac{1225}{2450}-\frac{1}{2450}\right)=\frac{153}{4900}\)
\(d,=\frac{5}{7}.\left(\frac{7}{1.5.8}+\frac{7}{5.8.12}+\frac{7}{8.12.15}+...+\frac{7}{33.36.40}\right)\)
\(=\frac{5}{7}.\left(\frac{8-1}{1.5.8}+\frac{12-5}{5.8.12}+\frac{15-8}{8.12.15}+...+\frac{40-33}{33.36.40}\right)\)
\(=\frac{5}{7}.\left(\frac{1}{1.5}-\frac{1}{5.8}+\frac{1}{5.8}-\frac{1}{8.12}+\frac{1}{8.12}-\frac{1}{12.15}+...+\frac{1}{33.36}-\frac{1}{36.40}\right)\)
\(=\frac{5}{7}.\left(\frac{1}{5}-\frac{1}{1440}\right)=\frac{5}{7}.\left(\frac{288}{1440}-\frac{1}{1440}\right)=\frac{41}{288}\)
P/S: . là nhân nha
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{1}{4}+\frac{3}{8}+\frac{5}{16}=\frac{5}{8}+\frac{5}{16}=\frac{15}{16}\)
\(\frac{3}{5}-\frac{1}{3}-\frac{1}{6}=\frac{4}{15}-\frac{1}{6}=\frac{1}{10}\)
\(\frac{4}{7}\cdot\frac{5}{8}\cdot\frac{7}{12}=\frac{4.5.7}{7.8.12}=\frac{140}{672}=\frac{5}{24}\)
\(\frac{25}{28}:\frac{15}{14}\cdot\frac{6}{7}=\frac{5}{6}\cdot\frac{6}{7}=\frac{5}{7}\)
\(\frac{1}{4}+\frac{3}{8}+\frac{5}{16}=\frac{15}{16}\)
\(\frac{3}{5}-\frac{1}{3}-\frac{1}{6}=\frac{1}{10}\)
\(\frac{4}{7}\times\frac{5}{8}\times\frac{7}{12}=\frac{5}{24}\)
\(\frac{25}{28}:\frac{15}{14}\times\frac{6}{7}=\frac{5}{7}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) = 17/19 - 17/19 + 27/35 + 35/35 = 0 + 62/35
b) = 1/3 x 4/5 + 1/3 x6/5 + 1/3 x 2 = 1/3(4/5 + 6/5 + 2) = 1/3 x 4 = = 4/3
c) 4/7 x 2/9 + 4/7 x 7/9 + 2/3 = 4/7 x (2/9 + 7/9) + 2/3 = 4/7 x 1 + 2/3 = 26/21
A) 17/19 - 17/19 + 27/35 + 35/35 = 0 + 62/35
B) 1/3 x 4/5 + 1/3 x 6/5 + 1/3 x 2 = 1/3 x(4/5 + 6/5 x 2 ) = 1/3 x 4 = 4/3
c) TƯƠNG TỰ CÂU A VÀ B
* HOKTOT*
NHA
thiếu đề
đề này là đổi từ hỗn số sang p/s à
vt đề đi
mk km choa
đề bài kiểu j v ạ