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mk vừa làm hoi này cho bạn mà
C=[(46-32)^2-(54-42)^2]*36-1872
=(14^2-12^2)*36-1872
=(196-144).36-1872
=52.36-1872
=1872-1872
=0
![](https://rs.olm.vn/images/avt/0.png?1311)
C=[(46-32)^2-(54-42)^2]*36-1872
=(14^2-12^2)*36-1872
=(196-144).36-1872
=52.36-1872
=1872-1872
=0
![](https://rs.olm.vn/images/avt/0.png?1311)
[(46-32)^2-(54-42)^2]*36-1872
=(14^2-12^2)*36-1872
=(196-144).36-1872
=52.36-1872
=1872-1872
=0
(x-7)^7=(x-7)^8
=>(x-7)^7-(x-7)^8=0
=>(x-7)^7.1-(x-7)^7.(x-7)=0
=>(x-7)^7.[1-(x-7)]=0
\(\Rightarrow\orbr{\begin{cases}x-7=0\\1-\left(x-7\right)=0\end{cases}\Rightarrow\orbr{\begin{cases}x=7;-7\\x=0\end{cases}}}\)
Vậy x={7;-7;0}
1+2^3+3^3-4^2.x=20
=>36-4^2.x=20
=>4^2.x=16=4^2
=>2.x=2
=>x=1
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left[\left(46-32\right)^2-\left(54-42\right)^2\right]\times36-1872\)
\(=\left(14^2-12^2\right)\times36-1872\)
\(=\left(196-144\right)\times36-1872\)
\(=52\times36-1872\)
\(=1872-1872\)
\(=0\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài làm
Sửa đề : \(\left(2x+3\right)-117=212\)( coppy lại đề nó vậy đấy, ko sao )
\(\Leftrightarrow2x+3=329\Leftrightarrow2x=326\Leftrightarrow x=163\)
(2x+ 3) - 117 = 212
=> 2x+ 3 = 212 + 171
2x+ 3 = 383
2x = 383 - 3
2x = 380
x = 380 : 2
x = 190
giúp mình nha
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left[\left(46-32\right)^2-\left(54-42\right)^2\right]\cdot36-1872\)
\(=\left[\left(14\right)^2-12^2\right]\cdot36-1872\)
\(=\left(196-144\right)\cdot36-1872\)
\(=52\cdot36-1872\)
\(=1872-1872\)
\(=0\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(100.x+\left(10+2\right)=212\)
\(\Leftrightarrow100x+\left(10+2\right)=212\)
\(\Leftrightarrow10x+12=212\)
\(\Leftrightarrow10x=200\)
\(\Leftrightarrow x=20\)
145+2(212-x)=512
2(212-x)= 512-145
2(212-x)= 377
(212-x)= 377:2
(212-x)= 188,5
x= 212-188,5
x= 24,5.
3x-1872=24 x 32
3x-1872=16x9
3x-1872=144
3x=144+1872
3x=2016
x=2016:3
x=672
146 + 2..(212-x) = 512
\(2.\left(212-x\right)=366\)
\(\left(212-x\right)=\frac{366}{2}\)
\(212-x=183\)
\(x=212-183\)
\(x=29\)