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2/3+1/3.(-4/9+5/6):7/12
=2/3+1/3.(-8/18+15/18):7/12
=2/3+1/3.7/18:7/12
=2/3+7/54:7/12
=2/3+7/54.12/7
=2/3+2/9
=6/9+2/9
=8/9
\(\frac{-5}{6}\)+ \((\frac{-6}{11}+1)\)=\(\frac{-5}{6}\)+\((\frac{-6}{11}+\frac{11}{11})\)=\(\frac{-5}{6}\)+\(\frac{5}{11}\)=\(\frac{-55}{66}+\frac{30}{66}\)=\(\frac{-25}{66}\)
1) \(\frac{5}{8}.\frac{7}{3}-\frac{5}{2}.\frac{1}{8}=\frac{5}{8}.\frac{7}{3}-\frac{5}{8}.\frac{1}{2}=\frac{5}{8}\left(\frac{7}{3}-\frac{1}{2}\right)=\frac{5}{8}.\frac{11}{6}=\frac{55}{48}\)
2) \(\frac{21}{10}.\frac{3}{4}-\frac{21}{10}.\frac{3}{4}=\frac{21}{10}\left(\frac{3}{4}-\frac{3}{4}\right)=\frac{21}{10}.0=0\)
3) \(\frac{-4}{11}:\frac{-6}{11}=\frac{-4}{11}.\frac{-11}{6}=\frac{-4.\left(-11\right)}{11.6}=\frac{-4.\left(-1\right)}{1.6}=\frac{4}{6}=\frac{2}{3}\)
4)\(\frac{2}{7}.\frac{14}{3}-1=\frac{2.14}{7.3}-1=\frac{2.2}{1.3}-1=\frac{4}{3}-1=\frac{1}{3}\)
5)\(\frac{4}{7}:\left(\frac{1}{5}.\frac{4}{7}\right)=\frac{4}{7}:\frac{4}{35}=\frac{4}{7}.\frac{35}{4}=\frac{4.35}{7.4}=\frac{1.5}{1.1}=5\)
6) \(\frac{12}{7}.\frac{7}{4}+\frac{35}{11}:\frac{245}{121}=\frac{12.7}{7.4}+\frac{35}{11}.\frac{121}{245}=\frac{3.1}{1.1}+\frac{35}{11}.\frac{121}{245}=3+\frac{35}{11}.\frac{121}{245}=3+\frac{35.121}{11.245}=\frac{1.11}{1.7}=\frac{11}{7}\)
a,x-6/7=5/2
x=5/2+6/7
x=47/14
b,12/7:x+2/3=7/5
12/7:x=7/5-2/3
12/7:x=11/15
x=12/7:11/15
x=180/77
c,2/3.x+3/4=3
2/3.x=3-3/4
2/3.x=9/4
x=9/4:2/3
x=27/8
d,720:[41-(2x-5)]=120
[41-(2x-5)]=720:120
[41-(2x-5)]=6
(2x-5)=41-6
(2x-5)=35
2x=35+5
2x=40
x=40:2
x=20
a; \(\dfrac{3}{5}\) - \(\dfrac{-7}{10}\) - \(\dfrac{13}{-20}\)
= \(\dfrac{12}{20}\) + \(\dfrac{14}{20}\) + \(\dfrac{13}{20}\)
= \(\dfrac{39}{20}\)
b; \(\dfrac{1}{2}\) + \(\dfrac{1}{-3}\) + \(\dfrac{1}{4}\) - \(\dfrac{-1}{6}\)
= \(\dfrac{6}{12}\) - \(\dfrac{4}{12}\) + \(\dfrac{3}{12}\) + \(\dfrac{2}{12}\)
= \(\dfrac{7}{12}\)
\(=-4910\)
=-4910