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ai giúp với huhu phần thưởng là 1 cái acc Bang bang cho ai trả lời đúng nếu người đó cần
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A = \(\frac{1}{2}.24\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\)
A = \(\frac{1}{2}\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\)
A = \(\frac{1}{2}\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\)
A = \(\frac{1}{2}\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\)
A = \(\frac{1}{2}\left(5^{16}-1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\)
A = \(\frac{1}{2}\left(5^{32}-1\right)\left(5^{32}+1\right)\)
A = \(\frac{1}{2}\left(5^{64}-1\right)\)
\(2A=24\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\)
\(=\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\)
\(=5^{64}-1\)
=> \(A=\frac{5^{64}-1}{2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1+1=2
k mình nha
1+1=2
Hok_Tốt
#Thiên_Hy