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a) Ta có:\(\left(3x-2^4\right)\cdot7^3=2\cdot7^4\)

\(\Leftrightarrow3x-16=2\cdot\dfrac{7^4}{7^3}=2\cdot7=14\)

\(\Leftrightarrow3x=30\)

hay x=10

Vậy: x=10

29 tháng 4 2021

(3x - 24) . 73 = 2. 74

3x - 2         = 2.74 : 73

3x - 16          = 14

3x                = 14 + 16

3x                = 30

x                  = 30 : 3 = 10

29 tháng 4 2021

a)(3x-2\(^4\)).7\(^3\)=2.7\(^4\)

   3x-2\(^4\)=2.7\(^4:7^3\)

   3x-16=2.7

   3x-16=14

   3x=30

  =>x=10

      Vậy x=10

 

a) Ta có:\(\left(3x-2^4\right)\cdot7^3=2\cdot7^4\)

\(\Leftrightarrow3x-16=2\cdot\dfrac{7^4}{7^3}=2\cdot7=14\)

\(\Leftrightarrow3x=30\)

hay x=10

Vậy: x=10

a:x=3/5-7/8=24/40-35/40=-11/40

b: =>1/3:(2x-1)=-1/6

=>2x-1=-2

=>2x=-1

=>x=-1/2

c: =>x-3/4=17/2+7/4=34/4+7/4=41/4

=>x=11

d: =>3x+2=0 hoặc 2/5x+7=0

=>x=-2/3 hoặc x=-7:2/5=-35/2

a: =>4/3x=7/9-4/9=1/3

=>x=1/4

b: =>5/2-x=9/14:(-4/7)=-9/8

=>x=5/2+9/8=29/8

c: =>3x+3/4=8/3

=>3x=23/12

hay x=23/36

d: =>-5/6-x=7/12-4/12=3/12=1/4

=>x=-5/6-1/4=-10/12-3/12=-13/12

10 tháng 4 2022

em moi lop 4 mà

 

2 tháng 6 2017

a) \(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{1}{10}\)

\(\dfrac{2}{3}x=\dfrac{1}{10}+\dfrac{1}{2}=\dfrac{3}{5}\)

\(x=\dfrac{3}{5}:\dfrac{2}{3}=\dfrac{9}{10}\)

b) \(\dfrac{39}{7}:x=13\)

\(x=\dfrac{\dfrac{39}{7}}{13}=\dfrac{3}{7}\)

c) \(\left(\dfrac{14}{5}x-50\right):\dfrac{2}{3}=51\)

\(\dfrac{14}{5}x-50=51\cdot\dfrac{2}{3}=34\)

\(\dfrac{14}{5}x=34+50=84\)

\(x=\dfrac{84}{\dfrac{14}{5}}=30\)

d) \(\left(x+\dfrac{1}{2}\right)\left(\dfrac{2}{3}-2x\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=0\\\dfrac{2}{3}-2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{1}{3}\end{matrix}\right.\)

e) \(\dfrac{2}{3}x-\dfrac{1}{2}x=\dfrac{5}{12}\)

\(\dfrac{1}{6}x=\dfrac{5}{12}\)

\(x=\dfrac{5}{12}:\dfrac{1}{6}=\dfrac{5}{2}\)

g) \(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\dfrac{11}{5}-\dfrac{3}{7}=-2\)

\(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\cdot\dfrac{11}{5}=-2+\dfrac{3}{7}=-\dfrac{11}{7}\)

\(x\cdot\dfrac{44}{7}+\dfrac{3}{7}=-\dfrac{11}{7}:\dfrac{11}{5}=-\dfrac{5}{7}\)

\(\dfrac{44}{7}x=-\dfrac{5}{7}-\dfrac{3}{7}=-\dfrac{8}{7}\)

\(x=-\dfrac{8}{7}:\dfrac{44}{7}=-\dfrac{2}{11}\)

h) \(\dfrac{13}{4}x+\left(-\dfrac{7}{6}\right)x-\dfrac{5}{3}=\dfrac{5}{12}\)

\(\dfrac{25}{12}x-\dfrac{5}{3}=\dfrac{5}{12}\)

\(\dfrac{25}{12}x=\dfrac{5}{12}+\dfrac{5}{3}=\dfrac{25}{12}\)

\(x=1\)

Mỏi tay woa bn làm nốt nha!!

9 tháng 1 2017

3x - 7 = 2x + 5

3x - 2x = 5 + 7

x = 12

|3x - 2| = 7

\(\Rightarrow\left\{\begin{matrix}3x-2=7\\-\left(3x-2\right)=7\end{matrix}\right.\Rightarrow\left\{\begin{matrix}3x=9\\-3x+2=7\end{matrix}\right.\)

\(\Rightarrow\left\{\begin{matrix}x=3\\-3x=5\end{matrix}\right.\Rightarrow\left\{\begin{matrix}x=3\\x=-\frac{5}{3}\end{matrix}\right.\)

4 - |x - 2| = -3

|x - 2| = 4 - (-3)

|x - 2| = 7

\(\Rightarrow\left\{\begin{matrix}x-2=7\\-\left(x-2\right)=7\end{matrix}\right.\Rightarrow\left\{\begin{matrix}x=9\\-x+2=7\end{matrix}\right.\)

\(\Rightarrow\left\{\begin{matrix}x=9\\-x=5\end{matrix}\right.\Rightarrow\left\{\begin{matrix}x=9\\x=-5\end{matrix}\right.\)

|2x - 3| = x - 1

\(\Rightarrow\left\{\begin{matrix}2x-3=x-1\\-\left(2x-3\right)=x-1\end{matrix}\right.\Rightarrow\left\{\begin{matrix}2x-x=-1+3\\-2x+3=x-1\end{matrix}\right.\)

\(\Rightarrow\left\{\begin{matrix}x=2\\-2x-x=-1-3\end{matrix}\right.\Rightarrow\left\{\begin{matrix}x=2\\-3x=-4\end{matrix}\right.\)

\(\Rightarrow\left\{\begin{matrix}x=2\\x=\frac{4}{3}\end{matrix}\right.\)

|3x + 1| = x + 3

\(\Rightarrow\left\{\begin{matrix}3x+1=x+3\\-\left(3x+1\right)=x+3\end{matrix}\right.\Rightarrow\left\{\begin{matrix}3x-x=3-1\\-3x-1=x+3\end{matrix}\right.\)

\(\Rightarrow\left\{\begin{matrix}2x=2\\-3x-x=3+1\end{matrix}\right.\Rightarrow\left\{\begin{matrix}x=1\\-4x=4\end{matrix}\right.\)

\(\Rightarrow\left\{\begin{matrix}x=1\\x=-1\end{matrix}\right.\)

8 tháng 11 2023

(3x-6)+3=3^2

3x+3=3^2

3*(x+1)=9

x+1=9:3

x+1=3

x=3-1=2

7 tháng 5 2019

\(a,x+\frac{3}{4}=\frac{1}{4}\)

\(\Rightarrow x=\frac{1}{4}-\frac{3}{4}=-\frac{1}{2}\)

\(b,\frac{2}{3}x-\frac{3}{7}=\frac{1}{7}\)

\(\Rightarrow\frac{2}{3}x=\frac{1}{7}+\frac{3}{7}\)

\(\Rightarrow\frac{2}{3}x=\frac{4}{7}\)

\(\Rightarrow x=\frac{4}{7}:\frac{2}{3}=\frac{4}{7}\cdot\frac{3}{2}=\frac{6}{7}\)

\(c,1\frac{2}{3}x-50\%x=-1\frac{1}{6}\)

\(\Rightarrow\frac{5}{3}x-\frac{50}{100}x=-\frac{7}{6}\)

\(\Rightarrow\left[\frac{5}{3}-\frac{50}{100}\right]x=-\frac{7}{6}\)

\(\Rightarrow\left[\frac{5}{3}-\frac{1}{2}\right]x=-\frac{7}{6}\)

\(\Rightarrow\frac{7}{6}x=-\frac{7}{6}\Leftrightarrow x=-\frac{7}{6}:\frac{7}{6}=-\frac{7}{6}\cdot\frac{6}{7}=-1\)

7 tháng 5 2019

a,x+\(\frac{3}{4}\)=\(\frac{1}{4}\)

=>x           =\(\frac{1}{4}\)-\(\frac{3}{4}\)

=> x          =\(\frac{-1}{2}\)   

Vậy x=\(\frac{-1}{2}\)

b,\(\frac{2}{3}\)x-\(\frac{3}{7}\)=\(\frac{1}{7}\)

=>\(\frac{2}{3}\)x          =\(\frac{1}{7}\)+\(\frac{3}{7}\)

=>\(\frac{2}{3}\)x           =\(\frac{4}{7}\)      

=>         x            =\(\frac{4}{7}\) :\(\frac{2}{3}\)

=>         x            =\(\frac{4}{7}\).\(\frac{3}{2}\)

=>         x             =\(\frac{6}{7}\)

Vậy x=\(\frac{6}{7}\)

c,\(\frac{12}{3}\)x-50%x   =\(\frac{-11}{6}\)

=>\(\frac{12}{3}\)x-\(\frac{1}{2}\)x=\(\frac{-11}{6}\)

=>x(\(\frac{12}{3}\)-\(\frac{1}{2}\))=\(\frac{-11}{6}\)

=>x(\(\frac{24}{6}\)-\(\frac{3}{6}\))=\(\frac{-11}{6}\)

=>x\(\frac{21}{6}\)              =\(\frac{-11}{6}\)

=>x                           =\(\frac{-11}{6}\):\(\frac{21}{6}\)

=>x                            =\(\frac{-11}{6}\).\(\frac{6}{21}\)

=>x                            =\(\frac{-11}{21}\)

Vậy x=\(\frac{-11}{21}\)

2 tháng 8 2018

Sorry bạn nha, mik chỉ làm câu a thôiViolympic toán 6

2 tháng 8 2018

cảm ơn bạn nhiều nha