A = ( 1 + 1/2 ) x ( 1 + 1/3 ) x ( 1 + 1/4 ) x .... x ( 1+ 1/100 )
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A=1/2x2/3x3/4x...x99/100
=>A=(1x2x3x...x99)/(2.3.4...100)
=>A=1/100
Vậy A = 1/100
\(A=\left(\frac{1-1}{2}\right).\left(\frac{1-1}{3}\right).\left(\frac{1-1}{4}\right)......\left(\frac{1-1}{100}\right)\)
\(A=\frac{0}{2}.\frac{0}{3}.\frac{0}{4}.......\frac{0}{100}\)
\(A=0.0.0.......0\)
\(A=0\)
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1.a) có: \(|x-\frac{3}{2}|,|x+1|,\left|x-2\right|\ge0\Rightarrow4x\ge0\Rightarrow x\ge0\)
\(x\ge0\Rightarrow x-\frac{3}{2}\ge\frac{-3}{2}\Rightarrow\left|x-\frac{3}{2}\right|\ge\left|\frac{-3}{2}\right|=\frac{3}{2}\Rightarrow\left|x-\frac{3}{2}\right|=x-\frac{3}{2}\)
cmtt: \(|x-2|=x-2\)
\(\Rightarrow3x-\frac{3}{2}+1-2=4x\)
\(\Rightarrow3x-\frac{5}{2}=4x\)
\(\Rightarrow x=\frac{-5}{2}\left(ko,t/m\right)\)
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a).( x - 1/2 )+( x - 1/4 ) = 1
x + x - 1/2 - 1/4 = 1
2x = 1/2 + 1/4 + 1
2x = 3/4 + 1
2x = 7/4
x = 7/4 : 2
x = 1/2
mik chỉ làm được như thế thôi xin lỗi bạn nhé
\(A=\left(1+\frac{1}{2}\right)\cdot\left(1+\frac{1}{3}\right)\cdot\left(1+\frac{1}{4}\right)\cdot....\cdot\left(1+\frac{1}{100}\right)\)
\(A=\frac{3\cdot4\cdot5\cdot...\cdot101}{2\cdot3\cdot4\cdot100}=\frac{101}{2}\)
\(\Rightarrow A=\frac{101}{2}\)
= 3/2 + 4/3 + ... + 101/100
= 3 + 4 + 5 + ... + 101/2 + 3 + 4 + ... + 100
= 101/2
k cho minh nha