X : 0, 25 + X x 11 = 39
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
39x11+25x11 =(39+25)x11
=64x11
=704
67x11+58x11=(67+58)x11
=125x11
=1375
39x11- 27x11
=(39-27)x11
=12x11
=132
Câu tự lấy ví dụ nhé
1) 39 x 11 + 25 x 11
= 11 x ( 39 + 25 ) = 11 x 64 = 704
67 x 11 + 58 x 11
= 11 x ( 67 + 58 ) = 11 x 125 = 1375
39 x 11 - 27 x 11
= ( 39 - 27 ) x 11 = 12 x 11 = 132
![](https://rs.olm.vn/images/avt/0.png?1311)
\(11\times\left(x-6\right)=4\times x+11\)
\(\Rightarrow11\times x-66=4\times x+11\)
\(\Rightarrow11\times x-4\times x=66+11\)
\(\Rightarrow77\times x=77\)
\(\Rightarrow x=1\)
b) \(\left(2\times x-10\right)\times\left(25-25\times x\right)=0\)
\(\Rightarrow\orbr{\begin{cases}2\times x-10=0\\25-25\times x=0\end{cases}\Rightarrow\orbr{\begin{cases}x=5\\x=1\end{cases}}}\)
a)11x(X-6)=4xX+11
11xX-11x6=4xX+11
11xX-4xX=11x6+11
(11-4)xX=66+11
7xX=77
x=77:7
x=11
b)(2xX-10)x(25-25xX)=0
=>2xX-10=0=>2xX=10 =>x=10:2=5
hoặc 25-25xX=0=>25xX=25=>x=25:25=1
Vậy x=1 hoặc x=5
Tích ch0 mình nha
Cảm ơn bạn nhìu
![](https://rs.olm.vn/images/avt/0.png?1311)
a) ( x- 55 ) . 17 = 0
x - 55 = 0 : 17
x - 55 = 0
x = 0 + 55
x = 55
Vậy x = 55
b) 25 . ( x - 75 ) = 25
x - 75 = 25 : 25
x - 75 = 1
x = 1 + 75
x = 76
Vậy x = 76
c) ( x - 5 ) ( x - 7 ) = 0
=> x - 5 = 0 hoặc x - 7 = 0
x = 0 + 5 x = 0 + 7
x = 5 x = 7
Vậy \(x\in\left\{5;7\right\}\)
d) ( x -11 ) ( x + 17 ) = 0
=> x - 11 = 0 hoặc x + 17 = 0
x = 0 + 11 x = 0 - 17
x = 11 x = -17
Vậy \(x\in\left\{11;-17\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(5x+x=39-3^{11}:3^9\)
\(\Leftrightarrow6x=39-3^2\)
\(\Leftrightarrow6x=30\)
\(\Leftrightarrow x=5\)
b) \(2^x:2^5=16\)
\(\Leftrightarrow2^x:2^5=2^4\)
\(\Leftrightarrow2^x=2^4.2^5\)
\(\Leftrightarrow2^x=2^9\)
\(\Leftrightarrow x=9\)
c) \(7x-x=5^{21}:5^{19}+3.2^2-7^0\)
\(\Leftrightarrow6x=5^2+3.4-1\)
\(\Leftrightarrow6x=36\)
\(\Leftrightarrow x=6\)
d) \(7x-2x=6^{17}:6^{15}+44:11\)
\(\Leftrightarrow5x=6^2+4\)
\(\Leftrightarrow5x=40\)
\(\Leftrightarrow x=8\)
a)⇔6x=39-32
⇔6x=30
⇔ x=5
b)2x:25=16
⇔2x=24.25
⇔ 2x=29
⇔ x=9
c)⇔6x=52+3.22-1
⇔ 6x= 36
⇔ x=6
d)⇔5x=62+4
⇔ 5x=40
⇔ x=8
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(x+\frac{9}{11}\right)\left(x-\frac{25}{31}\right)=0\)
\(=>\orbr{\begin{cases}x+\frac{9}{11}=0\\x-\frac{25}{31}=0\end{cases}}=>\orbr{\begin{cases}x=\frac{-9}{11}\\x=\frac{25}{31}\end{cases}}\)
Dấu \(\orbr{\begin{cases}\\\end{cases}}\)đó là hoặc nhé
![](https://rs.olm.vn/images/avt/0.png?1311)
Vì \(\left(x+\frac{9}{11}\right)\left(x-\frac{25}{31}=0\right)\)
\(\Rightarrow\orbr{\begin{cases}x+\frac{9}{11}=0\\x-\frac{25}{31}=0\end{cases}\Rightarrow\orbr{\begin{cases}x=-\frac{9}{11}\\x=\frac{25}{31}\end{cases}}}\)
Vậy :\(\orbr{\begin{cases}x=-\frac{9}{11}\\x=\frac{25}{31}\end{cases}}\)
Do (x+9/11)(x-25/31) = 0
=> x+9/11 = 0 hoặc x-25/31 = 0
+) Nếu x + 9/11 = 0 => x = 0 - 9/11 => x = -9/11
+) Nếu x - 25/31 = 0 => x = 0 + 25/31 => x = 25/31
KL: x = -9/11 hoặc x= 25/31
![](https://rs.olm.vn/images/avt/0.png?1311)
=>(x+9/11)=0 hoặc (x-25/31)=0
+/Nếu x+9/11=0
=>x=-9/11
+/Nếu x-25/31=0
=>x=25/31
`x:0,25+x xx11=39`
`=>x xx 4+x xx11=39`
`=>x xx (4+11)=39`
`=>x xx 15=39`
`=>x=39:15`
`=>x=13/5`