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27 tháng 7 2022

a) \(\left(\dfrac{1}{4}\right)^3.\left(\dfrac{1}{8}\right)^2=\left(\dfrac{1}{2}\right)^6.\left(\dfrac{1}{2}\right)^6=\left(\dfrac{1}{2}\right)^{12}\)

b) \(4^2.32:2^3=2^4.4.8:2^3=2^4.2^2.2^3:2^3=2^6\)

c) \(5^2.5^3.\dfrac{1}{5^4}.5^3\)\(=5^5.\dfrac{1}{5^4}.5^3=\dfrac{5^5}{5^4}.5^3=5.5^3=5^4\)

d) \(5^6.\dfrac{1}{20}.2^2.3^3:125=5^6.\dfrac{1}{5}.\dfrac{1}{4}.2^2.3^3:5^3\)\(=\dfrac{5^6}{5}.\dfrac{2^2}{4}.3^3:5^3=5^5.3^3:5^3=5^2.3^3\)

11 tháng 6 2023

`(1 1/4)^10 . (2/5)^20`

`=(5/4)^10 . (2/5)^20`

`=(5^10 .2^20)/(4^10 .5^20)`

`=(5^10 .4^10)/(4^10 .5^20)`

`=1/(5^10)`

`=(1/5)^10`

a: \(=2^2\cdot9\cdot\dfrac{1}{6\cdot9}\cdot\dfrac{4^2}{9^2}=\dfrac{2^2}{6}\cdot\dfrac{2^4}{3^4}=\dfrac{2^6}{2\cdot3\cdot3^4}=\dfrac{2^5}{3^5}=\left(\dfrac{2}{3}\right)^5\)

b: \(=2^8\cdot\dfrac{3^4}{2^4}=3^4\cdot2^4=6^4\)

c: \(=\dfrac{\left(\dfrac{1}{2}\right)^3\cdot2^3\cdot\left(\dfrac{1}{2}\right)^2}{\left(-8\right)^2\cdot16}\cdot2^6=\dfrac{\dfrac{1}{2^2}}{64\cdot16}\cdot64=\dfrac{1}{4}:16=\dfrac{1}{64}=\left(\dfrac{1}{8}\right)^2\)

a: \(=2^2\cdot9\cdot\dfrac{1}{3^3\cdot2}\cdot\dfrac{2^4}{3^4}=\dfrac{2^4\cdot2^2}{2}\cdot\dfrac{9}{3^3\cdot3^4}=\dfrac{2^5}{3^5}=\left(\dfrac{2}{3}\right)^5\)

b: \(=2^8\cdot\dfrac{3^4}{2^4}=3^4\cdot2^4=6^4\)

c: \(=\dfrac{\dfrac{1}{2^3}\cdot\dfrac{1}{2^2}\cdot8}{\left(-8\right)^2\cdot2^4}\cdot2^6=\dfrac{1}{2^2}\cdot2^6:2^{10}=\dfrac{2^4}{2^{10}}=\dfrac{1}{2^6}=\left(\dfrac{1}{8}\right)^2\)

a: \(=\dfrac{3^3\cdot2^6}{3^{-4}\cdot2^6}=3^7\)

b: \(=\left(\dfrac{3}{7}\right)^5\cdot\left(\dfrac{3}{7}\right)\cdot\dfrac{5^6}{3^6}:\left(\dfrac{625}{343}\right)^2\)

\(=\dfrac{3^6}{7^6}\cdot\dfrac{5^6}{3^6}:\dfrac{5^8}{7^6}\)

\(=\dfrac{1}{5^2}\)

c: \(=5^{4+3}\cdot\left(\dfrac{5}{2}\right)^{-5}\cdot\dfrac{1}{25}\)

\(=5^5\cdot\left(\dfrac{2}{5}\right)^5=2^5\)

a: \(=\dfrac{3^3\cdot2^6}{3^{-4}\cdot2^6}=3^7\)

b: \(=\left(\dfrac{3}{7}\right)^5\cdot\left(\dfrac{3}{7}\right)\cdot\dfrac{5^6}{3^6}:\left(\dfrac{625}{343}\right)^2\)

\(=\dfrac{3^6}{7^6}\cdot\dfrac{5^6}{3^6}:\dfrac{5^8}{7^6}\)

\(=\dfrac{1}{5^2}\)

c: \(=5^{4+3}\cdot\left(\dfrac{5}{2}\right)^{-5}\cdot\dfrac{1}{25}\)

\(=5^5\cdot\left(\dfrac{2}{5}\right)^5=2^5\)

a: \(=\dfrac{3^3\cdot2^6}{3^{-4}\cdot2^6}=3^7\)

b: \(=\left(\dfrac{3}{7}\right)^5\cdot\left(\dfrac{3}{7}\right)\cdot\dfrac{5^6}{3^6}:\left(\dfrac{625}{343}\right)^2\)

\(=\dfrac{3^6}{7^6}\cdot\dfrac{5^6}{3^6}:\dfrac{5^8}{7^6}\)

\(=\dfrac{1}{5^2}\)

c: \(=5^{4+3}\cdot\left(\dfrac{5}{2}\right)^{-5}\cdot\dfrac{1}{25}\)

\(=5^5\cdot\left(\dfrac{2}{5}\right)^5=2^5\)

a: \(=\dfrac{3^3\cdot2^6}{3^{-4}\cdot2^6}=3^7\)

b: \(=\left(\dfrac{3}{7}\right)^5\cdot\left(\dfrac{3}{7}\right)\cdot\dfrac{5^6}{3^6}:\left(\dfrac{625}{343}\right)^2\)

\(=\dfrac{3^6}{7^6}\cdot\dfrac{5^6}{3^6}:\dfrac{5^8}{7^6}\)

\(=\dfrac{1}{5^2}\)

c: \(=5^{4+3}\cdot\left(\dfrac{5}{2}\right)^{-5}\cdot\dfrac{1}{25}\)

\(=5^5\cdot\left(\dfrac{2}{5}\right)^5=2^5\)

17 tháng 11 2021

D,       Vì 3^2=9 và -3^2=9 còn 5^2=25

17 tháng 11 2021

D

 

a: \(=\dfrac{3^3\cdot2^6}{3^{-4}\cdot2^6}=3^7\)

b: \(=\left(\dfrac{3}{7}\cdot\dfrac{5}{3}\right)^6\cdot\dfrac{5}{3}\cdot\dfrac{3}{7}:\left(\dfrac{7^3}{5^4}\right)^{-2}\)

\(=\left(\dfrac{5}{7}\right)^6\cdot\dfrac{5}{7}\cdot\left(\dfrac{5}{7}\right)^6\cdot5^2\)

\(=\left(\dfrac{5}{7}\right)^{13}\cdot5^2\)

c: \(=5^4\cdot2.5^{-5}\cdot125\cdot0.04\)

\(=5^4\cdot5\cdot\left(\dfrac{5}{2}\right)^{-5}\)

\(=5^5\cdot\left(\dfrac{2}{5}\right)^5=2^5\)

a) (1/4)3 x (1/8)2

= [(1/2)2]3 x [(1/2)3]2

= (1/2)6 x (1/2)6

= (1/2)12

b) 4x 32: 23

= (22)2 x 25: 23

= 24 x 25: 23

= 24 x 22

= 26

c) 25 x 53 x 1/625 x 53

= 52x 53 x (1/5)4 x 5

= (1/5)4 x 58

= 1/54 x 5(giải thích nếu ko hiểu: (1/5)4= 14/54= 1/54)

= 58/54

= 54 

d) 56 x 1/20 x 2x 32 : 125

= 56/20 x (2x3)2 : 53

= 56/ (5x4) x 62: 53

= 55/4 x 62/53 (62/53 là dạng phân số, bản chất vẫn là lấy 62 chia 53)

= 55 x 62/ 4x 53 (nhân phân số: tử nhân tử, mẫu nhân mẫu)
= 52x 62/ 22 (chia 55 cho 53 ra 52)

= 302/ 22

= 152

*Kiến thức áp dụng:
amx an = am+n

am: an= am-n

(am)n = am x n

am x bm = (a x b)m