\(\frac{x-3}{2-x}=\frac{-2}{3}\).Tìm x nha.
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Có \(\frac{\frac{2}{7}+\frac{2}{5}+\frac{2}{17}-\frac{2}{239}}{\frac{3}{239}-\frac{3}{7}-\frac{3}{5}-\frac{3}{17}}\) : \(\frac{x}{3}\) = 2
\(\frac{2.\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}-\frac{1}{239}\right)}{-3.\left(\frac{-1}{239}+\frac{1}{7}+\frac{1}{5}+\frac{1}{17}\right)}\) : \(\frac{x}{3}\) = 2
\(\frac{-2}{3}\) : \(\frac{x}{3}\) = 2
\(\frac{-2}{3}\) . \(\frac{3}{x}\) = 2
\(\frac{-2}{x}\) = 2
\(\Rightarrow\) x = -1
Vậy x = -1
Chúc bạn học tốt !!! ^^ #Mango
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{x-1}{x+2}=\frac{x-2}{x+3}\)
\(\frac{x-1}{x+2}-\frac{x-2}{x+3}=0\)
\(\frac{\left(x-1\right)\left(x+3\right)}{\left(x+2\right)\left(x+3\right)}-\frac{\left(x-2\right)\left(x+2\right)}{\left(x+2\right)\left(x+3\right)}=0\)
\(\frac{x^2+2x-3-x^2+4}{x^2+5x+6}=0\)
\(\frac{2x+1}{x^2+5x+6}=0\)
\(\Rightarrow2x+1=0\)
\(\Rightarrow x=\frac{-1}{2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{x+\frac{3}{2}}{x-\frac{2}{3}}\)VÌ \(x-\frac{2}{3}< x+\frac{3}{2}\)=> \(x-\frac{2}{3}< 0;x+\frac{3}{2}>0\)
=> \(\frac{-3}{2}< x< \frac{2}{3}\)=> \(x=\left\{-\frac{8}{6};-\frac{7}{6};....;\frac{3}{6}\right\}\)
HỌC TỐT NHA
![](https://rs.olm.vn/images/avt/0.png?1311)
a, Đề có vẻ sai sai nhé :v
b, \(\left|\frac{1}{2}x-\frac{2}{3}\right|-1=\frac{1}{6}\)
\(\Leftrightarrow\left|\frac{1}{2}x-\frac{2}{3}\right|=\frac{7}{6}\)
\(\Leftrightarrow\orbr{\begin{cases}\frac{1}{2}x-\frac{2}{3}=\frac{7}{6}\\\frac{1}{2}x-\frac{2}{3}=-\frac{7}{6}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{11}{3}\\x=-1\end{cases}}\)
Vậy : ....
c, \(\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+...+\frac{2}{x(x+1)}=\frac{4}{5}\)
\(\Leftrightarrow\frac{2}{2\cdot3}+\frac{2}{3\cdot4}+\frac{2}{4\cdot5}+...+\frac{2}{x\cdot(x+1)}=\frac{4}{5}\)
\(\Leftrightarrow2\left[\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{x}-\frac{1}{x+1}\right]=\frac{4}{5}\)
\(\Leftrightarrow2\left[\frac{1}{2}-\frac{1}{x+1}\right]=\frac{4}{5}\)
\(\Leftrightarrow\frac{1}{2}-\frac{1}{x+1}=\frac{2}{5}\)
\(\Leftrightarrow\frac{1}{x+1}=\frac{1}{10}\)
\(\Leftrightarrow x+1=10\Leftrightarrow x=9\)
Vậy x = 9
![](https://rs.olm.vn/images/avt/0.png?1311)