x nhân 9 -x nhân 2+ x=56
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![](https://rs.olm.vn/images/avt/0.png?1311)
\(9x-5x+3x=56\)
<=> \(7x=56\)
<=> \(x=8\)
Vậy...
\(9x-x+3x=165\)
<=> \(11x=165\)
<=> \(x=15\)
Vậy....
\(7x+8x-x=168\)
<=> \(14x=168\)
<=> \(x=12\)
Vậy...
\(\frac{5}{8}x-\frac{1}{3}x-\frac{1}{6}x=15\)
<=> \(\frac{1}{8}x=15\)
<=> \(x=120\)
Vậy...
Dấu . là dấu nhân nha
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a, 9 . x - 5 . x + 3 . x = 56
x . (9 - 5 + 3) = 56
x . 7 = 56
x = 56 : 7
x = 8
b, 9 . x - x + 3 . x = 165
x . (9 - 1 + 3) = 165
x . 11 = 165
x = 165 : 11
x = 15
c, 7 . x + 8 . x - x = 168
x . (7 + 8 - 1) = 168
x . 14 = 168
x = 168 : 14
x = 12
d, 5/8 . x - 1/3 . x - 1/6 . x = 15
x . (5/8 - 1/3 - 1/6) = 15
x . 1/8 = 15
x = 15 : 1/8
x = 120
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
`a. =4(x^2+4x+3)=4(x^2+3x+x+3)=4(x+3)(x+1)`
`b. =x^2+8x-7x-56=x(x+8)-7(x+8)=(x+8)(x-7)`
`c. =x^2-9x+8x-72=x(x-9)+8(x-9)=(x-9)(x+8)`
`d. =(x-y)^2-9=(x-y-3)(x-y+3)`
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(26+5\times x=3\times x+56\)
\(5\times x-3\times x=56-26\)
\(x\times\left(5-3\right)=30\)
\(x\times2=30\)
x=30:2
x=15
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{x}{3\frac{1}{2}.2\frac{2}{3}}=\frac{9}{56}\Rightarrow\frac{x}{\frac{7}{2}.\frac{8}{3}}=\frac{9}{56}\Rightarrow x=\frac{9}{56}.\frac{28}{3}=\frac{3}{2}\)
\(x:\left(3\frac{1}{2}.2\frac{2}{3}\right)=\frac{9}{56}\)
\(x:\left(\frac{7}{2}.\frac{8}{3}\right)=\frac{9}{56}\)
\(x:\left(\frac{7.4}{3}\right)=\frac{9}{56}\)
\(x.\frac{3}{28}=\frac{9}{56}\)
\(x=\frac{9}{56}.\frac{28}{3}=\frac{3}{2}\)
Vậy \(x=\frac{3}{2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(-5\right)^2.x=56+22x\)
\(\Leftrightarrow25x=56+22x\)
\(\Leftrightarrow25x-22x=56\)
\(\Leftrightarrow3x=56\)
\(\Rightarrow x=\frac{56}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
=> x . ( 2 + 3 + 4 + 5 + 6 ) = x . 9 + 9999
=> x . 20 = x . 9 + 9999
=> x . 11 = 9999 ( cùng bớt x + 9 )
=> x = 9999 : 11
=> 909
2x + 3x + 4x + 20x + 6x = 9x + 9999
35x - 9x = 9999
26x = 9999
x = 9999 / 26
Vậy : x = 9999 / 26
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có :\(x+2x+3x+...+9x=459-9\)
\(\Rightarrow\)\(x\left(1+2+3+...+9\right)=450\)
\(\frac{\Rightarrow x.\left[\left(9-1\right):1+1\right].\left(9+1\right)}{2}\)\(=450\)
\(\frac{\Rightarrow x.90}{2}=450\)
\(\Rightarrow x.90=450.2=900\)
\(\Rightarrow x=\frac{900}{90}\)
\(\Rightarrow x=10\)
\(\text{Tìm }x\text{ : }\)
\(\text{Ta có : }\)
\(x+2x+3x+...+9x=459-9\)
\(\Rightarrow\text{ }x+2x+3x+...+9x=450\)
\(\Rightarrow\text{ }x\cdot\left(\left(9-1\right)\text{ : }1+1\right)\cdot\left(\left(9+1\right)\text{ : }2\right)=450\)
\(\Rightarrow\text{ }x\cdot\left(8\text{ : }1+1\right)\cdot\left(\left(9+1\right)\text{ : }2\right)=450\)
\(\Rightarrow\text{ }x\cdot\left(8+1\right)\cdot\left(\left(9+1\right)\text{ : }2\right)=450\)
\(\Rightarrow\text{ }x\cdot9\cdot\left(\left(9+1\right)\text{ : }2\right)=450\)
\(x\cdot9\cdot\left(10\text{ : }2\right)=450\)
\(x\cdot9\cdot5=450\)
\(x\cdot45=450\)
\(x=450\text{ : }45\)
\(x=10\)
X x 9 - X x 2 + X=56
X x (9 -2+1) =56
X x 8 =56
X =7
CHÚC EM HT
X x 9 -X x 2 + X =56
<=>X x (9-2+1)=56
<=>X x 8 =56
<=>x=56:8
<=>x=7