(-14)+5+17+14 tính một cách hợp lí
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= 11/125 - [(17/18 - 4/9) + (5/7 - 17/14)]
= 11/125 - (1/2 - 1/2)
= 11/125
\(\dfrac{11}{125}-\dfrac{17}{18}-\dfrac{5}{7}+\dfrac{4}{9}+\dfrac{17}{14}=\dfrac{11}{125}-\left(\dfrac{17}{18}-\dfrac{4}{9}\right)+\left(\dfrac{17}{14}-\dfrac{5}{7}\right)=\dfrac{11}{125}-\dfrac{17-4.2}{18}+\dfrac{17-5.2}{14}=\dfrac{11}{125}-\dfrac{9}{18}+\dfrac{7}{14}=\dfrac{11}{125}-\dfrac{1}{2}+\dfrac{1}{2}=\dfrac{11}{125}\)
\(a,=\dfrac{14}{13}-\dfrac{1}{13}-\dfrac{19}{20}\\ =1-\dfrac{19}{20}=\dfrac{20}{20}-\dfrac{19}{20}\\ =\dfrac{1}{20}\\ b,=\dfrac{-24}{17}+\dfrac{7}{17}+\dfrac{1}{16}\\ =-1+\dfrac{1}{16}\\ =\dfrac{-16}{16}+\dfrac{1}{16}=\dfrac{-15}{16}\)
11 - 12 + 13 - 14 + 15 - 16 + 17 - 18 + 19 -20
= (11 + 19) - (12 + 18) + (13 + 17) - (14 + 16) - (20 - 15)
= 30 - 30 + 30 - 30 - 5
= 0 + 0 - 5
= - 5
34 + 35 + 36 + 37 – 14 – 15 – 16 – 17
= (34 – 14) + (35 – 15) + (36 – 16 ) + (37 -17)
= 20 + 20 + 20 + 20 = 80
\(A=\frac{-3}{7}+\frac{14}{23}+\frac{-14}{17}+\frac{9}{23}-\frac{5}{19}\)
\(\Rightarrow A=-\frac{3}{7}+\left(\frac{14}{23}+\frac{9}{23}\right)-\frac{14}{17}-\frac{5}{19}\)
\(\Rightarrow A=\frac{-3}{7}+1-\frac{14}{17}-\frac{5}{19}\)
Tính nốt nhé
\(B=\frac{5}{9}.\frac{7}{13}.\frac{5}{9}.\frac{9}{13}.\left(-\frac{5}{13}\right).\frac{3}{9}\)
Tương tự câu A
11-12+13-14+15-16+17-18+19-20
=(11-12)+(13-14)+(15-16)+(17-18)+(19-20)
=(-1)+(-1)+(-1)+(-1)+(-1)
=-1.5
=-5
ta co
11-12+13-14+15-16+17-18+19-20\
= (11-12)+(13-14)+(15-16)+(17-18)+(19-20)
=(-1)+(-1)+(-1)+(-1)+(-1)
=(-1)x5
=-5
a) 35-{12-[-14+(-2)]}.
= 35 - 12 + 14 + 2
= 35 + 14 - (12 - 2)
= 49 - 10
= 39
b) 160:{17+[9×5-(14+2048:256)]}.
= 160: {17 + [45 - (14 + 8)]}
= 160: {17 + [45 - 22)]}
= 160:{17 + 23}
= 160: 40 = 4
c) 20210-{225:[20×15-8×25]-25}.
= 1 - {225:[300 - 200] - 25}
= 1 - {225 : 100 - 25}
= 1 - {2,25 - 25}
= 1 + 25 - 2,25
= 23,75
\(=\left(-14+14\right)+5+17\)
\(=0+5+17\)
\(=22\)
( -14) +5+17+14
= [( -14)+14] +5+17
= 0 +5+17
= 5+17
=22