tính biểu thức sau:(1/2:3/5). 0,5
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\(P=\left(-0,5-\frac{3}{5}\right):\left(-3\right)+\frac{1}{3}-\left(-\frac{1}{6}\right):\left(-2\right)\)
\(P=\left(-\frac{11}{10}\right):\left(-3\right)+\frac{1}{3}-\frac{1}{12}\)
\(P=\frac{11}{30}+\frac{1}{4}\)
\(P=\frac{37}{60}\)
\(Q=\left(\frac{2}{25}-1,008\right):\frac{4}{7}:\left[\left(\frac{13}{4}-\frac{59}{9}\right).\frac{36}{17}\right]\)
\(Q=\left(-\frac{116}{125}\right):\frac{4}{7}:\left(-7\right)\)
\(Q=\left(-\frac{203}{125}\right):\left(-7\right)\)
\(Q=\frac{29}{125}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
P=(-0,5-3/5):(-3)+1/3-(-1/6):(-2)
=(-1/2-3/5):(-3)+1/3+1/6:(-2)
= -9/10: -4/3+1/12
= -27/40+1/12
=-71/120
![](https://rs.olm.vn/images/avt/0.png?1311)
Bạn tham khảo bài của mình ở dưới nha! (Bạn nên đăng 1 lần thôi)
![](https://rs.olm.vn/images/avt/0.png?1311)
Mình nghĩ đk sau biểu thức sẽ là \(0,5\le x\le3\)
Ta có: \(0,5\le x\le3\)
\(\Leftrightarrow\) \(\left\{{}\begin{matrix}2x-1\ge0\\3-x\ge0\end{matrix}\right.\)
\(\Rightarrow\) \(\left(2x-1\right)\left(3-x\right)\ge0\)
Dấu "=" xảy ra khi \(\left[{}\begin{matrix}2x-1=0\\3-x=0\end{matrix}\right.\) \(\Leftrightarrow\) \(\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=3\end{matrix}\right.\left(TM\right)\)
Vậy ...
Chúc bn học tốt!
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{5^3.3^5}{5^3.0,5+125.2,5}\)
\(=\frac{5^3.3^5}{5^3.0,5+5^3.2,5}\)
\(=\frac{5^3.3^5}{5^3\left(0,5+2,5\right)}\)
\(=\frac{5^3.3^5}{5^3.3}\)
\(=3^4=81\)
#Học tốt!!!
~NTTH~
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{2^3.\left(0,5\right)^3.3^7}{2.\left(0,5\right)^4.3^8}=\frac{2^3.\left(\frac{1}{2}\right)^3.3^7}{2.\left(\frac{1}{2}\right)^4.3^8}=\frac{2^3.\frac{1^3}{2^3}.3^7}{2.\frac{1^4}{2^4}.3^8}=\frac{1.3^7}{\frac{1}{2^3}.3^8}=\frac{3^7}{\frac{3^8}{2^3}}=3^7.\frac{2^3}{3^8}=\frac{2^3}{3}=\frac{8}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)
\(\begin{array}{l}\left( {0,25 - \frac{5}{6}} \right).1,6 + \frac{{ - 1}}{3}\\ =(\frac{25}{100}-\frac{5}{6}).\frac{16}{10}+\frac{-1}{3}\\= \left( {\frac{1}{4} - \frac{5}{6}} \right).\frac{8}{5} + \frac{{ - 1}}{3}\\ = \left( {\frac{6}{{24}} - \frac{{20}}{{24}}} \right).\frac{8}{5} + \frac{{ - 1}}{3}\\ = \frac{{ - 14}}{{24}}.\frac{8}{5} + \frac{{ - 1}}{3}\\ = \frac{{ - 14}}{{15}} + \frac{{ - 1}}{3}\\ = \frac{{ - 14}}{{15}} + \frac{{ - 5}}{{15}}\\ = \frac{{ - 19}}{{15}}\end{array}\)
b)
\(\begin{array}{l}3 - 2.\left[ {0,5 + \left( {0,25 - \frac{1}{6}} \right)} \right]\\ = 3 - 2.\left[ {\frac{1}{2} + \left( {\frac{1}{4} - \frac{1}{6}} \right)} \right]\\ = 3 - 2.\left( {\frac{1}{2} + \frac{1}{{12}}} \right)\\ =3-2.(\frac{6}{12}+\frac{1}{12})\\= 3 - 2.\frac{7}{{12}}\\ = 3 - \frac{7}{6}\\=\frac{18}{6}-\frac{7}{6}\\ = \frac{{11}}{6}\end{array}\)