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7\10=7 nhân 9 và 10 nhân 9=63/90
8/9=8 nhân 10 và 9 nhân 10=8o/90
b12/7=12 nhân 15 và 7 nhân 15=225 và 105
9/15=9 nhân 15 và 7 nhân 7 =63 /105
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{9}{12}=\dfrac{135}{180}\)
\(\dfrac{7}{15}=\dfrac{84}{180}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Ta có: \(12 = 2^2 . 3; 15 = 3.5\)
\(BCNN(12, 15) = 2^2.3.5 = 60\) nên chọn mẫu chung là 60.
\(\begin{array}{l}\frac{9}{{12}} = \frac{{9.5}}{{12.5}} = \frac{{45}}{{60}}\\\frac{7}{{15}} = \frac{{7.4}}{{15.4}} = \frac{{28}}{{60}}\end{array}\)
b) Ta có: \(10 = 2.5; 4 = 2^2; 14=2.7\)
\(BCNN(10, 4, 14) =2^2.5.7= 140\) nên chọn mẫu chung là 140.
\(\begin{array}{l}\frac{7}{{10}} = \frac{{7.14}}{{10.14}} = \frac{{98}}{{140}}\\\frac{3}{4} = \frac{{3.35}}{{4.35}} = \frac{{105}}{{140}}\\\frac{9}{{14}} = \frac{{9.10}}{{14.10}} = \frac{{90}}{{140}}\end{array}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{9}{12}=\dfrac{45}{60}\)
\(\dfrac{7}{15}=\dfrac{28}{60}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(\dfrac{-7}{15}=\dfrac{-7\cdot4}{15\cdot4}=\dfrac{-28}{60}\)
\(\dfrac{5}{12}=\dfrac{5\cdot5}{12\cdot5}=\dfrac{25}{60}\)
b: \(\dfrac{1}{5}=\dfrac{1\cdot6}{5\cdot6}=\dfrac{6}{30}\)
\(\dfrac{-2}{3}=\dfrac{-2\cdot10}{3\cdot10}=\dfrac{-20}{30}\)
\(\dfrac{7}{10}=\dfrac{7\cdot3}{10\cdot3}=\dfrac{21}{30}\)
c: \(\dfrac{-15}{50}=\dfrac{-15\cdot3}{50\cdot3}=\dfrac{-45}{150}\)
\(\dfrac{9}{10}=\dfrac{9\cdot15}{10\cdot15}=\dfrac{135}{150}\)
\(\dfrac{26}{-30}=\dfrac{-26}{30}=\dfrac{-26\cdot5}{30\cdot5}=\dfrac{-130}{150}\)
d: \(\dfrac{7}{10}=\dfrac{7\cdot51}{10\cdot51}=\dfrac{357}{510}\)
\(\dfrac{-5}{-15}=\dfrac{1}{3}=\dfrac{1\cdot170}{3\cdot170}=\dfrac{170}{510}\)
\(\dfrac{3}{17}=\dfrac{3\cdot30}{17\cdot30}=\dfrac{90}{510}\)
e: \(\dfrac{-4}{-75}=\dfrac{4}{75}=\dfrac{4}{75}\)
\(\dfrac{-3}{5}=\dfrac{-3\cdot15}{5\cdot15}=\dfrac{-45}{75}\)
\(\dfrac{8}{25}=\dfrac{8\cdot3}{25\cdot3}=\dfrac{24}{75}\)
f: \(-\dfrac{4}{5}=\dfrac{-4\cdot7}{5\cdot7}=\dfrac{-28}{35}\)
\(\dfrac{6}{7}=\dfrac{6\cdot5}{7\cdot5}=\dfrac{30}{35}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{-9}{12}+\left(-10\right)\)
\(=\frac{-9}{12}-\frac{10}{1}=\frac{-9}{12}-\frac{120}{12}=\frac{-9-120}{12}\)
\(=\frac{-129}{12}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{9}{12}=\dfrac{45}{60}\)
\(\dfrac{7}{15}=\dfrac{28}{60}\)
3x12/9x12=36/108
10x9/12x9=90/108